Quartz Scheduler: How to pass custom objects as JobParameter?

拜拜、爱过 提交于 2019-11-28 11:58:51

There are two ways to pass an object that can be retrieved when a Quartz job executes:

Pass the instance in the data map. When you set the job up, add your instance to the map with a key like this:

// Create job etc...
var MyClass _myInstance;
statusJob.JobDataMap.Put("myKey", _myInstance);
// Schedule job...

Retrieve the instance in the job's Execute() method like this:

public void Execute(IJobExecutionContext context)
        {
            var dataMap = context.MergedJobDataMap;
            var myInstance = (MyClass)dataMap["myKey"];

OR

Add the instance to the scheduler context when you set the job up, like this:

  ISchedulerFactory schedFact = new StdSchedulerFactory();
  _sched = schedFact.GetScheduler();
  _sched.Start();
  // Create job etc...
  var MyClass _myInstance;
  _sched.Context.Put("myKey", myInstance);
  // Schedule job...

Retrieve the instance in the job's Execute() method like this:

public void Execute(IJobExecutionContext context)
        {
            var schedulerContext = context.Scheduler.Context;
            var myInstance = (MyClass)schedulerContext.Get("myKey");

When you schedule a job you can set a JobDataMap on the JobDetail object and pass this to your scheduler, there are some limitations described in the quartz.net tutorial. The job can access the data via:

JobDataMap dataMap = context.JobDetail.JobDataMap;

However I prefer to access my job configuration, via an repository injected into the job.

I was having unexpected results with hillstuk's answer above in multithreaded environments. Here's my solution using Newtonsoft… Enjoy

public void InitJob() {

    MyClass data = new MyClass {Foo = “Foo fighters”}; 

    /* a unique identifier for demonstration purposes.. Use your own concoction here. */
    int uniqueIdentifier = new Random().Next(int.MinValue, int.MaxValue); 

    IJobDetail newJob = JobBuilder.Create<MyAwesomeJob>()
    .UsingJobData("JobData", JsonConvert.SerializeObject(data))
    .WithIdentity($"job-{uniqueIdentifier}", "main")                
    .Build();

}

/* the execute method */
public class MyAwesomeJob : IJob
{
    public void Execute(IJobExecutionContext context)
    {                   
        var jobData = JsonConvert.DeserializeObject<MyClass>(context.JobDetail.JobDataMap.GetString("JobData"));    
    }
}

/* for completeness */
public class MyClass {
    string Foo { get; set; } 
}

You can put your instance/object in the IJobDetail.

 JobDataMap m = new JobDataMap();
  m.Put("Class1", new Class1(){name="xxx"});


  IJobDetail job = JobBuilder.Create<Job>()
            .WithIdentity("myJob", "group1")
            .UsingJobData(m)//class object
            .UsingJobData("name2", "Hello World!")
            .Build();

usage

  public void Execute(IJobExecutionContext context)
        {
 JobDataMap dataMap = context.JobDetail.JobDataMap;
            Class1 class1 = (Class1)dataMap.Get("Class1");
string x = class1.name;
}

I passed the object following way

JobDetail job1 = JobBuilder.newJob(JobAutomation.class)
                .usingJobData("path", path)
                .withIdentity("job2", "group2").build();

        CronTrigger trigger1 = TriggerBuilder.newTrigger()
                .withIdentity("cronTrigger2", "group2")
                .withSchedule(CronScheduleBuilder.cronSchedule("40 27 11 * * ?"))
                .build();

get jobdatamap by following lines of code

JobDataMap dataMap = context.getJobDetail().getJobDataMap();
String path =dataMap.getString("path");
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!