I'm making a function to return the number of decimal and whole number digits and am converting the inserted typename
number to a string using sstream
s.
However the number when being converted to a string comes out in scientific notations which is not useful for counting the number of digits are in the normal number. How can I stop this from happening in my function below?
enum { DECIMALS = 10, WHOLE_NUMBS = 20, ALL = 30 };
template < typename T > int Numbs_Digits(T numb, int scope)
{
stringstream ss(stringstream::in | stringstream::out);
stringstream ss2(stringstream::in | stringstream::out);
unsigned long int length = 0;
unsigned long int numb_wholes;
ss2 << (int) numb;
numb_wholes = ss2.str().length();
ss2.flush();
bool all = false;
switch (scope) {
case ALL:
all = true;
case DECIMALS:
ss << numb;
length += ss.str().length() - (numb_wholes + 1); // +1 for the "."
if (all != true)
break;
case WHOLE_NUMBS:
length += numb_wholes;
if (all != true)
break;
default:
break;
}
return length;
}
Use std::fixed
stream manipulator as:
ss << fixed << numb;
--
Example,
#include <iostream>
using namespace std;
int main () {
double a,b,c;
a = 3.1415926534;
b = 2006.0;
c = 1.0e-10;
cout.precision(5);
cout << a << '\t' << b << '\t' << c << endl;
cout << fixed << a << '\t' << b << '\t' << c << endl;
cout << scientific << a << '\t' << b << '\t' << c << endl;
return 0;
}
Output:
3.1416 2006 1e-010
3.14159 2006.00000 0.00000
3.14159e+000 2.00600e+003 1.00000e-010
Example is taken from here.
And you can use std::stringstream
instead of cout
, but the result would be same. Experiment it here:
You need to use stream manipulators to format the string as you want it. In your case, you will probably want to use the fixed
format flag :
ss << std::fixed << numb;
The opposite (if you ever want to force scientific notation) is the scientific
format flag :
ss << std::scientific << numb;
来源:https://stackoverflow.com/questions/6010838/how-to-stop-doubles-converting-to-scientific-notation-when-using-a-stringstream