问题
Using Linux and Python, I want to send some data with broadcast:
d = b'109u433279423423423'
import socket
s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
s.sendto(d, 0, ('192.168.0.255', 9))
I launch this script under root and get this error:
s.sendto(d, 0, ('192.168.0.255', 9)) socket.error: [Errno 13]
Permission denied
What is wrong?
回答1:
You are trying to send to a broadcast address. It is not allowed, see manpage for sendto(2):
EACCES (For UDP sockets) An attempt was made to send to a network/broadcast address as though it was a unicast address.
Set the SO_BROADCAST option, if you actually mean to send to a broadcast address:
s.setsockopt(socket.SOL_SOCKET, socket.SO_BROADCAST, 1)
来源:https://stackoverflow.com/questions/11457676/python-socket-error-errno-13-permission-denied