Jenkins Read a Specific Line of a File in Jenkinsfile with Groovy

问题

I am trying to read a specific line of an html file in a Jenkins stage with Groovy and save its contents to an environment variable. The problem is, File and readLines() are not allowed.

I am able to load a file with

env.WORKSPACE = pwd()
def file = readFile "${env.WORKSPACE}/file.html"

Provided in this answer

But how can I access instantly to the contents of line n? I am using Jenkins 2.32

回答1:

Just going to leave documented here, but you can also use readLines().

def file = readFile location
def lines = file.readLines()

From this other question

回答2:

I Tried the suggestion of tim_yates from the comments but System was also forbidden. What ultimately worked for me was just changing System.getProperty("line.separator") to new line character "\n".

So the full answer was in its simplicity:

file.split("\n")[n]

来源：https://stackoverflow.com/questions/43740474/jenkins-read-a-specific-line-of-a-file-in-jenkinsfile-with-groovy