问题
I have a MySQL table which is as follows:
id | name | parent_id |
---|---|---|
19 | category1 | 0 |
20 | category2 | 19 |
21 | category3 | 20 |
22 | category4 | 21 |
... | ... | ... |
Now, I want to have a single MySQL query to which I simply supply the id [for instance say id=19
] then I should get all its child ids [i.e. result should have ids '20,21,22']....
The hierarchy of the children is not known; it can vary....
I know how to do it using a for
loop... but how to achieve the same using a single MySQL query?
回答1:
For MySQL 8+: use the recursive with syntax.
For MySQL 5.x: use inline variables, path IDs, or self-joins.
MySQL 8+
with recursive cte (id, name, parent_id) as (
select id,
name,
parent_id
from products
where parent_id = 19
union all
select p.id,
p.name,
p.parent_id
from products p
inner join cte
on p.parent_id = cte.id
)
select * from cte;
The value specified in parent_id = 19
should be set to the id
of the parent you want to select all the descendants of.
MySQL 5.x
For MySQL versions that do not support Common Table Expressions (up to version 5.7), you would achieve this with the following query:
select id,
name,
parent_id
from (select * from products
order by parent_id, id) products_sorted,
(select @pv := '19') initialisation
where find_in_set(parent_id, @pv)
and length(@pv := concat(@pv, ',', id))
Here is a fiddle.
Here, the value specified in @pv := '19'
should be set to the id
of the parent you want to select all the descendants of.
This will work also if a parent has multiple children. However, it is required that each record fulfills the condition parent_id < id
, otherwise the results will not be complete.
Variable assignments inside a query
This query uses specific MySQL syntax: variables are assigned and modified during its execution. Some assumptions are made about the order of execution:
- The
from
clause is evaluated first. So that is where@pv
gets initialised. - The
where
clause is evaluated for each record in the order of retrieval from thefrom
aliases. So this is where a condition is put to only include records for which the parent was already identified as being in the descendant tree (all descendants of the primary parent are progressively added to@pv
). - The conditions in this
where
clause are evaluated in order, and the evaluation is interrupted once the total outcome is certain. Therefore the second condition must be in second place, as it adds theid
to the parent list, and this should only happen if theid
passes the first condition. Thelength
function is only called to make sure this condition is always true, even if thepv
string would for some reason yield a falsy value.
All in all, one may find these assumptions too risky to rely on. The documentation warns:
you might get the results you expect, but this is not guaranteed [...] the order of evaluation for expressions involving user variables is undefined.
So even though it works consistently with the above query, the evaluation order may still change, for instance when you add conditions or use this query as a view or sub-query in a larger query. It is a "feature" that will be removed in a future MySQL release:
Previous releases of MySQL made it possible to assign a value to a user variable in statements other than
SET
. This functionality is supported in MySQL 8.0 for backward compatibility but is subject to removal in a future release of MySQL.
As stated above, from MySQL 8.0 onward you should use the recursive with
syntax.
Efficiency
For very large data sets this solution might get slow, as the find_in_set operation is not the most ideal way to find a number in a list, certainly not in a list that reaches a size in the same order of magnitude as the number of records returned.
Alternative 1: with recursive
, connect by
More and more databases implement the SQL:1999 ISO standard WITH [RECURSIVE] syntax for recursive queries (e.g. Postgres 8.4+, SQL Server 2005+, DB2, Oracle 11gR2+, SQLite 3.8.4+, Firebird 2.1+, H2, HyperSQL 2.1.0+, Teradata, MariaDB 10.2.2+). And as of version 8.0, also MySQL supports it. See the top of this answer for the syntax to use.
Some databases have an alternative, non-standard syntax for hierarchical look-ups, such as the CONNECT BY
clause available on Oracle, DB2, Informix, CUBRID and other databases.
MySQL version 5.7 does not offer such a feature. When your database engine provides this syntax or you can migrate to one that does, then that is certainly the best option to go for. If not, then also consider the following alternatives.
Alternative 2: Path-style Identifiers
Things become a lot easier if you would assign id
values that contain the hierarchical information: a path. For example, in your case this could look like this:
ID | NAME |
---|---|
19 | category1 |
19/1 | category2 |
19/1/1 | category3 |
19/1/1/1 | category4 |
Then your select
would look like this:
select id,
name
from products
where id like '19/%'
Alternative 3: Repeated Self-joins
If you know an upper limit for how deep your hierarchy tree can become, you can use a standard sql
query like this:
select p6.parent_id as parent6_id,
p5.parent_id as parent5_id,
p4.parent_id as parent4_id,
p3.parent_id as parent3_id,
p2.parent_id as parent2_id,
p1.parent_id as parent_id,
p1.id as product_id,
p1.name
from products p1
left join products p2 on p2.id = p1.parent_id
left join products p3 on p3.id = p2.parent_id
left join products p4 on p4.id = p3.parent_id
left join products p5 on p5.id = p4.parent_id
left join products p6 on p6.id = p5.parent_id
where 19 in (p1.parent_id,
p2.parent_id,
p3.parent_id,
p4.parent_id,
p5.parent_id,
p6.parent_id)
order by 1, 2, 3, 4, 5, 6, 7;
See this fiddle
The where
condition specifies which parent you want to retrieve the descendants of. You can extend this query with more levels as needed.
回答2:
From the blog Managing Hierarchical Data in MySQL
Table structure
+-------------+----------------------+--------+
| category_id | name | parent |
+-------------+----------------------+--------+
| 1 | ELECTRONICS | NULL |
| 2 | TELEVISIONS | 1 |
| 3 | TUBE | 2 |
| 4 | LCD | 2 |
| 5 | PLASMA | 2 |
| 6 | PORTABLE ELECTRONICS | 1 |
| 7 | MP3 PLAYERS | 6 |
| 8 | FLASH | 7 |
| 9 | CD PLAYERS | 6 |
| 10 | 2 WAY RADIOS | 6 |
+-------------+----------------------+--------+
Query:
SELECT t1.name AS lev1, t2.name as lev2, t3.name as lev3, t4.name as lev4
FROM category AS t1
LEFT JOIN category AS t2 ON t2.parent = t1.category_id
LEFT JOIN category AS t3 ON t3.parent = t2.category_id
LEFT JOIN category AS t4 ON t4.parent = t3.category_id
WHERE t1.name = 'ELECTRONICS';
Output
+-------------+----------------------+--------------+-------+
| lev1 | lev2 | lev3 | lev4 |
+-------------+----------------------+--------------+-------+
| ELECTRONICS | TELEVISIONS | TUBE | NULL |
| ELECTRONICS | TELEVISIONS | LCD | NULL |
| ELECTRONICS | TELEVISIONS | PLASMA | NULL |
| ELECTRONICS | PORTABLE ELECTRONICS | MP3 PLAYERS | FLASH |
| ELECTRONICS | PORTABLE ELECTRONICS | CD PLAYERS | NULL |
| ELECTRONICS | PORTABLE ELECTRONICS | 2 WAY RADIOS | NULL |
+-------------+----------------------+--------------+-------+
Most users at one time or another have dealt with hierarchical data in a SQL database and no doubt learned that the management of hierarchical data is not what a relational database is intended for. The tables of a relational database are not hierarchical (like XML), but are simply a flat list. Hierarchical data has a parent-child relationship that is not naturally represented in a relational database table. Read more
Refer the blog for more details.
EDIT:
select @pv:=category_id as category_id, name, parent from category
join
(select @pv:=19)tmp
where parent=@pv
Output:
category_id name parent
19 category1 0
20 category2 19
21 category3 20
22 category4 21
Reference: How to do the Recursive SELECT query in Mysql?
回答3:
Try these:
Table definition:
DROP TABLE IF EXISTS category;
CREATE TABLE category (
id INT AUTO_INCREMENT PRIMARY KEY,
name VARCHAR(20),
parent_id INT,
CONSTRAINT fk_category_parent FOREIGN KEY (parent_id)
REFERENCES category (id)
) engine=innodb;
Experimental rows:
INSERT INTO category VALUES
(19, 'category1', NULL),
(20, 'category2', 19),
(21, 'category3', 20),
(22, 'category4', 21),
(23, 'categoryA', 19),
(24, 'categoryB', 23),
(25, 'categoryC', 23),
(26, 'categoryD', 24);
Recursive Stored procedure:
DROP PROCEDURE IF EXISTS getpath;
DELIMITER $$
CREATE PROCEDURE getpath(IN cat_id INT, OUT path TEXT)
BEGIN
DECLARE catname VARCHAR(20);
DECLARE temppath TEXT;
DECLARE tempparent INT;
SET max_sp_recursion_depth = 255;
SELECT name, parent_id FROM category WHERE id=cat_id INTO catname, tempparent;
IF tempparent IS NULL
THEN
SET path = catname;
ELSE
CALL getpath(tempparent, temppath);
SET path = CONCAT(temppath, '/', catname);
END IF;
END$$
DELIMITER ;
Wrapper function for the stored procedure:
DROP FUNCTION IF EXISTS getpath;
DELIMITER $$
CREATE FUNCTION getpath(cat_id INT) RETURNS TEXT DETERMINISTIC
BEGIN
DECLARE res TEXT;
CALL getpath(cat_id, res);
RETURN res;
END$$
DELIMITER ;
Select example:
SELECT id, name, getpath(id) AS path FROM category;
Output:
+----+-----------+-----------------------------------------+
| id | name | path |
+----+-----------+-----------------------------------------+
| 19 | category1 | category1 |
| 20 | category2 | category1/category2 |
| 21 | category3 | category1/category2/category3 |
| 22 | category4 | category1/category2/category3/category4 |
| 23 | categoryA | category1/categoryA |
| 24 | categoryB | category1/categoryA/categoryB |
| 25 | categoryC | category1/categoryA/categoryC |
| 26 | categoryD | category1/categoryA/categoryB/categoryD |
+----+-----------+-----------------------------------------+
Filtering rows with certain path:
SELECT id, name, getpath(id) AS path FROM category HAVING path LIKE 'category1/category2%';
Output:
+----+-----------+-----------------------------------------+
| id | name | path |
+----+-----------+-----------------------------------------+
| 20 | category2 | category1/category2 |
| 21 | category3 | category1/category2/category3 |
| 22 | category4 | category1/category2/category3/category4 |
+----+-----------+-----------------------------------------+
回答4:
The best approach I've come up with is
- Use lineage to store\sort\trace trees. That's more than enough, and works thousands times faster for reading than any other approach. It also allows to stay on that pattern even if DB will change(as ANY db will allow that pattern to be used)
- Use function that determines lineage for specific ID.
- Use it as you wish (in selects, or on CUD operations, or even by jobs).
Lineage approach descr. can be found wherever, for example Here or here. As of function - that is what enspired me.
In the end - got more-or-less simple, relatively fast, and SIMPLE solution.
Function's body
-- --------------------------------------------------------------------------------
-- Routine DDL
-- Note: comments before and after the routine body will not be stored by the server
-- --------------------------------------------------------------------------------
DELIMITER $$
CREATE DEFINER=`root`@`localhost` FUNCTION `get_lineage`(the_id INT) RETURNS text CHARSET utf8
READS SQL DATA
BEGIN
DECLARE v_rec INT DEFAULT 0;
DECLARE done INT DEFAULT FALSE;
DECLARE v_res text DEFAULT '';
DECLARE v_papa int;
DECLARE v_papa_papa int DEFAULT -1;
DECLARE csr CURSOR FOR
select _id,parent_id -- @n:=@n+1 as rownum,T1.*
from
(SELECT @r AS _id,
(SELECT @r := table_parent_id FROM table WHERE table_id = _id) AS parent_id,
@l := @l + 1 AS lvl
FROM
(SELECT @r := the_id, @l := 0,@n:=0) vars,
table m
WHERE @r <> 0
) T1
where T1.parent_id is not null
ORDER BY T1.lvl DESC;
DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = TRUE;
open csr;
read_loop: LOOP
fetch csr into v_papa,v_papa_papa;
SET v_rec = v_rec+1;
IF done THEN
LEAVE read_loop;
END IF;
-- add first
IF v_rec = 1 THEN
SET v_res = v_papa_papa;
END IF;
SET v_res = CONCAT(v_res,'-',v_papa);
END LOOP;
close csr;
return v_res;
END
And then you just
select get_lineage(the_id)
Hope it helps somebody :)
回答5:
Did the same thing for another quetion here
Mysql select recursive get all child with multiple level
The query will be :
SELECT GROUP_CONCAT(lv SEPARATOR ',') FROM (
SELECT @pv:=(
SELECT GROUP_CONCAT(id SEPARATOR ',')
FROM table WHERE parent_id IN (@pv)
) AS lv FROM table
JOIN
(SELECT @pv:=1)tmp
WHERE parent_id IN (@pv)
) a;
回答6:
If you need quick read speed, the best option is to use a closure table. A closure table contains a row for each ancestor/descendant pair. So in your example, the closure table would look like
ancestor | descendant | depth
0 | 0 | 0
0 | 19 | 1
0 | 20 | 2
0 | 21 | 3
0 | 22 | 4
19 | 19 | 0
19 | 20 | 1
19 | 21 | 3
19 | 22 | 4
20 | 20 | 0
20 | 21 | 1
20 | 22 | 2
21 | 21 | 0
21 | 22 | 1
22 | 22 | 0
Once you have this table, hierarchical queries become very easy and fast. To get all the descendants of category 20:
SELECT cat.* FROM categories_closure AS cl
INNER JOIN categories AS cat ON cat.id = cl.descendant
WHERE cl.ancestor = 20 AND cl.depth > 0
Of course, there is a big downside whenever you use denormalized data like this. You need to maintain the closure table alongside your categories table. The best way is probably to use triggers, but it is somewhat complex to correctly track inserts/updates/deletes for closure tables. As with anything, you need to look at your requirements and decide what approach is best for you.
Edit: See the question What are the options for storing hierarchical data in a relational database? for more options. There are different optimal solutions for different situations.
回答7:
Simple query to list child's of first recursion:
select @pv:=id as id, name, parent_id
from products
join (select @pv:=19)tmp
where parent_id=@pv
Result:
id name parent_id
20 category2 19
21 category3 20
22 category4 21
26 category24 22
... with left join:
select
@pv:=p1.id as id
, p2.name as parent_name
, p1.name name
, p1.parent_id
from products p1
join (select @pv:=19)tmp
left join products p2 on p2.id=p1.parent_id -- optional join to get parent name
where p1.parent_id=@pv
The solution of @tincot to list all child's:
select id,
name,
parent_id
from (select * from products
order by parent_id, id) products_sorted,
(select @pv := '19') initialisation
where find_in_set(parent_id, @pv) > 0
and @pv := concat(@pv, ',', id)
Test it online with Sql Fiddle and see all results.
http://sqlfiddle.com/#!9/a318e3/4/0
回答8:
You can do it like this in other databases quite easily with a recursive query (YMMV on performance).
The other way to do it is to store two extra bits of data, a left and right value. The left and right value are derived from a pre-order traversal of the tree structure you're representing.
This is know as Modified Preorder Tree Traversal and lets you run a simple query to get all parent values at once. It also goes by the name "nested set".
回答9:
Just use BlueM/tree php class for make tree of a self-relation table in mysql.
Tree and Tree\Node are PHP classes for handling data that is structured hierarchically using parent ID references. A typical example is a table in a relational database where each record’s “parent” field references the primary key of another record. Of course, Tree cannot only use data originating from a database, but anything: you supply the data, and Tree uses it, regardless of where the data came from and how it was processed. read more
Here is an example of using BlueM/tree:
<?php
require '/path/to/vendor/autoload.php'; $db = new PDO(...); // Set up your database connection
$stm = $db->query('SELECT id, parent, title FROM tablename ORDER BY title');
$records = $stm->fetchAll(PDO::FETCH_ASSOC);
$tree = new BlueM\Tree($records);
...
回答10:
Something not mentioned here, although a bit similar to the second alternative of the accepted answer but different and low cost for big hierarchy query and easy (insert update delete) items, would be adding a persistent path column for each item.
some like:
id | name | path
19 | category1 | /19
20 | category2 | /19/20
21 | category3 | /19/20/21
22 | category4 | /19/20/21/22
Example:
-- get children of category3:
SELECT * FROM my_table WHERE path LIKE '/19/20/21%'
-- Reparent an item:
UPDATE my_table SET path = REPLACE(path, '/19/20', '/15/16') WHERE path LIKE '/19/20/%'
Optimise the path length and ORDER BY path
using base36 encoding instead real numeric path id
// base10 => base36
'1' => '1',
'10' => 'A',
'100' => '2S',
'1000' => 'RS',
'10000' => '7PS',
'100000' => '255S',
'1000000' => 'LFLS',
'1000000000' => 'GJDGXS',
'1000000000000' => 'CRE66I9S'
https://en.wikipedia.org/wiki/Base36
Suppressing also the slash '/' separator by using fixed length and padding to the encoded id
Detailed optimization explanation here: https://bojanz.wordpress.com/2014/04/25/storing-hierarchical-data-materialized-path/
TODO
building a function or procedure to split path for retreive ancestors of one item
回答11:
Based on the @trincot answer, very good explained, I use WITH RECURSIVE ()
statement to create a breadcrumb using id
of the current page and go backwards in the hierarchy to find the every parent
in my route
table.
So, the @trincot solution is adapted here in the opposite direction to find parents instead of descendants.
I also added depth
value which is usefull to invert result order (otherwise the breadcrumb would be upside down).
WITH RECURSIVE cte (
`id`,
`title`,
`url`,
`icon`,
`class`,
`parent_id`,
`depth`
) AS (
SELECT
`id`,
`title`,
`url`,
`icon`,
`class`,
`parent_id`,
1 AS `depth`
FROM `route`
WHERE `id` = :id
UNION ALL
SELECT
P.`id`,
P.`title`,
P.`url`,
P.`icon`,
P.`class`,
P.`parent_id`,
`depth` + 1
FROM `route` P
INNER JOIN cte
ON P.`id` = cte.`parent_id`
)
SELECT * FROM cte ORDER BY `depth` DESC;
Before upgrade to mySQL 8+, I was using vars but it's deprecated and no more working on my 8.0.22 version !
回答12:
Its a little tricky one, check this whether it is working for you
select a.id,if(a.parent = 0,@varw:=concat(a.id,','),@varw:=concat(a.id,',',@varw)) as list from (select * from recursivejoin order by if(parent=0,id,parent) asc) a left join recursivejoin b on (a.id = b.parent),(select @varw:='') as c having list like '%19,%';
SQL fiddle link http://www.sqlfiddle.com/#!2/e3cdf/2
Replace with your field and table name appropriately.
回答13:
It's a category table.
SELECT id,
NAME,
parent_category
FROM (SELECT * FROM category
ORDER BY parent_category, id) products_sorted,
(SELECT @pv := '2') initialisation
WHERE FIND_IN_SET(parent_category, @pv) > 0
AND @pv := CONCAT(@pv, ',', id)
Output::
回答14:
This works for me, hope this will work for you too. It will give you a Record set Root to Child for any Specific Menu. Change the Field name as per your requirements.
SET @id:= '22';
SELECT Menu_Name, (@id:=Sub_Menu_ID ) as Sub_Menu_ID, Menu_ID
FROM
( SELECT Menu_ID, Menu_Name, Sub_Menu_ID
FROM menu
ORDER BY Sub_Menu_ID DESC
) AS aux_table
WHERE Menu_ID = @id
ORDER BY Sub_Menu_ID;
回答15:
I found it more easily to :
1) create a function that will check if a item is anywhere in the parent hierarchy of another one. Something like this (I will not write the function, make it with WHILE DO) :
is_related(id, parent_id);
in your example
is_related(21, 19) == 1;
is_related(20, 19) == 1;
is_related(21, 18) == 0;
2) use a sub-select , something like this:
select ...
from table t
join table pt on pt.id in (select i.id from table i where is_related(t.id,i.id));
回答16:
I have made a query for you. This will give you Recursive Category with a Single Query:
SELECT id,NAME,'' AS subName,'' AS subsubName,'' AS subsubsubName FROM Table1 WHERE prent is NULL
UNION
SELECT b.id,a.name,b.name AS subName,'' AS subsubName,'' AS subsubsubName FROM Table1 AS a LEFT JOIN Table1 AS b ON b.prent=a.id WHERE a.prent is NULL AND b.name IS NOT NULL
UNION
SELECT c.id,a.name,b.name AS subName,c.name AS subsubName,'' AS subsubsubName FROM Table1 AS a LEFT JOIN Table1 AS b ON b.prent=a.id LEFT JOIN Table1 AS c ON c.prent=b.id WHERE a.prent is NULL AND c.name IS NOT NULL
UNION
SELECT d.id,a.name,b.name AS subName,c.name AS subsubName,d.name AS subsubsubName FROM Table1 AS a LEFT JOIN Table1 AS b ON b.prent=a.id LEFT JOIN Table1 AS c ON c.prent=b.id LEFT JOIN Table1 AS d ON d.prent=c.id WHERE a.prent is NULL AND d.name IS NOT NULL
ORDER BY NAME,subName,subsubName,subsubsubName
Here is a fiddle.
来源:https://stackoverflow.com/questions/65769869/query-using-loop