MySQL You are using safe update mode and you tried to update a table without a WHERE

旧巷老猫 提交于 2021-02-15 05:33:07

问题


I have been getting this error message from mySQL

"Error Code: 1175. You are using safe update mode and you tried to update a table without a WHERE that uses a KEY column To disable safe mode, toggle the option in Preferences -> SQL Editor and reconnect. "

The query I use is this:

 UPDATE table1 a INNER JOIN table2 asa ON a.ID = asa.Table1Id SET a.ReferenceID = asa.ReferenceID WHERE a.ID > 0 AND asa.ID > 0 

I do have where clauses for both tables on IDs which are Primary key for both tables.

Disabling the SQL_SAFE_UPDATES is not an option.

Edit: MySQL version is v5.6


回答1:


It seems that MySQL 5.6 is limited about executing an UPDATE statement along with a JOIN

So, instead of

UPDATE table1 a
INNER JOIN table2 asa
ON a.ID = asa.Table1Id
SET a.ReferenceID = asa.ReferenceID
WHERE a.ID > 0 AND asa.ID > 0

You'll have to write as many queries as needed like :

UPDATE table1 a
SET a.ReferenceID = <The corresponding value in table 2>
WHERE a.ID = <The corresponding ID>

This being pretty annoying to type, one can use dynamic SQL to build the update queries :

SELECT CONCAT('UPDATE table1 a SET a.ReferenceID = ', asa.ReferenceID, ' WHERE a.ID = ', t.ID, ';')
FROM table1 t
INNER JOIN table2 asa
ON t.ID = asa.Table1Id;

In example :

Schema (MySQL v5.6)

CREATE TABLE test
(
    id INT NOT NULL PRIMARY KEY AUTO_INCREMENT,
    foo VARCHAR(255)
);

CREATE TABLE test2
(
    id INT NOT NULL PRIMARY KEY AUTO_INCREMENT,
    id_test INT NOT NULL,
    foo VARCHAR(255),
    FOREIGN KEY (id_test) REFERENCES test(id)
);

INSERT INTO test (foo) VALUES ('hello'), ('world');

INSERT INTO test2 (id_test, foo) VALUES (1, 'bar'), (2, 'baz');

Query #1

SELECT CONCAT('UPDATE test t SET t.foo = ''', t2.foo, ''' WHERE t.id = ', t.id, ';') AS 'sql query'
FROM test t
INNER JOIN test2 t2
ON t.id = t2.id_test;

This outputs :

UPDATE test t SET t.foo = 'bar' WHERE t.id = 1;
UPDATE test t SET t.foo = 'baz' WHERE t.id = 2;

The output can now be used to manually update the differents rows


View on DB Fiddle




回答2:


Even though you are using the KEYS,I guess the KEYS are not properly used. MySQL documentation says.

If this variable is enabled, UPDATE and DELETE statements that do not use a key in the WHERE clause or a LIMIT clause produce an error. This makes it possible to catch UPDATE and DELETE statements where keys are not used properly and that would probably change or delete a large number of rows.

Your query below will affect same number of rows even with WHERE conditions. I suppose all the values of ID is more than 0 right? If so,then that is the reason for your error.

 UPDATE table1 a 
 INNER JOIN table2 asa 
 ON a.ID = asa.Table1Id 
 SET a.ReferenceID = asa.ReferenceID 
 --WHERE a.ID > 0 AND asa.ID > 0 

One way is as suggested SET SQL_SAFE_UPDATES=0; (disable and try). Or try refining the WHERE condition. Also you can use LIMIT if it is a single table.



来源:https://stackoverflow.com/questions/59842134/mysql-you-are-using-safe-update-mode-and-you-tried-to-update-a-table-without-a-w

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