How to delete rows from a csv file based on a list values from another file?

问题

I have two files:

candidates.csv:

id,value
1,123
4,1
2,5
50,5

blacklist.csv:

I'd like to remove all rows from candidates.csv in which the first column (id) has a value contained in blacklist.csv. id is always numeric. In this case I'd like my output to look like this:

id,value
4,1
50,5

So far, my script for identifying the duplicate lines looks like this:

cat candidates.csv | cut -d \, -f 1 | grep -f blacklist.csv -w

This gives me the output

1
2

Now I somehow need to pipe this information back into sed/awk/gawk/... to delete the duplicates, but I don't know how. Any ideas how I can continue from here? Or is there a better solution altogether? My only restriction is that it has to run in bash.

回答1:

What about the following:

 awk -F, '(NR==FNR){a[$1];next}!($1 in a)' blacklist.csv candidates.csv

How does this work?

An awk program is a series of pattern-action pairs, written as:

condition { action }
condition { action }
...

where condition is typically an expression and action a series of commands. Here, the first condition-action pairs read:

(NR==FNR){a[$1];next} if the total record count NR equals the record count of the file FNR (i.e. if we are reading the first file), store all values in array a and skip to the next record (do not do anything else)
!($1 in a) if the first field is not in the array a then perform the default action which is print the line. This will only work on the second file as the condition of the first condition-action pair does not hold.

回答2:

If you are not too concerned about the order of the lines in your candidates.csv file you could use the following:

join -v 1 -t, <(sort -t, candidates.csv) <(sort blacklist.csv)

The -v 1 requests all the lines from the first file (the sorted candidates.csv) which do not match on the first field with the second file (the blacklist.csv). The -t, just sets the comma as a separator.

If you're concerned about the header line in the candidates.csv file you could strip it before the sorting or change the order.

回答3:

You can use sed and grep together to get the output

$ sed -e 's/[0-9]+/&\,/g' blacklist.csv > filter.csv
$ grep -Fvf filter.csv candidates.csv
id,value
4,1
50,5

sed command adds a , to each id and output to a filter.csv. E is to interprete regex in MacOSX/FreeBSD, same as -r in GNU sed.

grep uses the option f to compare between files, then remove the lines using v. F is for fixed string.

来源：https://stackoverflow.com/questions/52649404/how-to-delete-rows-from-a-csv-file-based-on-a-list-values-from-another-file

标签

bash

csv

awk

sed

grep