问题
I know that there are several other question/answers similar to this, but I haven't read one that addresses my confusion over this transform. I need to move an XML document from this format:
<root>
<row>
<t0>1</t0>
<title>Main Title</title>
</row>
<row>
<t0>2</t0>
<title>Secondary Title</title>
<note>Note</note>
</row>
<row>
<t0>3</t0>
<title>Tertiary Title</title>
</row>
<row>
<t0>3</t0>
<title>Another Title</title>
</row>
<row>
<t0>2</t0>
<title>A Second Secondary Title</title>
<note>Note</note>
</row>
<row>
<t0>3</t0>
<title>Third Level Title</title>
</row>
<row>
<t0>3</t0>
<title>Title at Level Three</title>
</row>
</root>
to this format:
<root>
<header>List</header>
<t01>
<title>Main Title</title>
<t02>
<title>Secondary Title</title>
<note>Note</note>
<t03>
<title>Tertiary Title</title>
</t03>
<t03>
<title>Another Title</title>
</t03>
</t02>
<t02>
<title>A Second Secondary Title</title>
<note>Note</note>
<t03>
<title>Third Level Title</title>
</t03>
<t03>
<title>Title at Level Three</title>
</t03>
</t02>
</t01>
</root>
I'm using XSLT 2.0 and I'm getting hung up on applying for-each-group recursively. Thanks for your time & trouble.
回答1:
With XSLT 2.0 I would strongly suggest to use the for-each-grouping
together with a recursive function or template; below is a sample using a function:
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="2.0"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:mf="http://example.com/mf"
exclude-result-prefixes="xs mf">
<xsl:output indent="yes"/>
<xsl:function name="mf:group" as="element()*">
<xsl:param name="elements" as="element(row)*"/>
<xsl:param name="level" as="xs:integer"/>
<xsl:for-each-group select="$elements" group-starting-with="row[t0 = $level]">
<xsl:element name="t{format-number($level, '00')}">
<xsl:copy-of select="* except t0"/>
<xsl:sequence select="mf:group(current-group() except ., $level + 1)"/>
</xsl:element>
</xsl:for-each-group>
</xsl:function>
<xsl:template match="root">
<xsl:copy>
<header>List</header>
<xsl:sequence select="mf:group(row, 1)"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
回答2:
Please give this a try:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/root">
<root>
<header>List</header>
<xsl:apply-templates select="row[t0 = 1]" />
</root>
</xsl:template>
<xsl:template match="row">
<xsl:variable name="level" select="t0" />
<xsl:element name="{concat('t0', $level)}">
<xsl:apply-templates select="title | note" />
<xsl:variable name="nextPeer"
select="following-sibling::row[t0 <= $level]" />
<xsl:variable name="children"
select="following-sibling::row[t0 = $level + 1][not($nextPeer)
or (count(preceding-sibling::row) < count($nextPeer[1]/preceding-sibling::row))]" />
<xsl:apply-templates select="$children" />
</xsl:element>
</xsl:template>
</xsl:stylesheet>
来源:https://stackoverflow.com/questions/14341145/xslt-how-to-apply-recursion-to-transform-from-a-flat-file-to-a-nested-tree