问题
im currently looking into kivy to start with crossplatform development. i have a bit of python experience (but basic) and now wanted to code a little game in kivy to get into. i probably wont finish this but i like learning stuff while doing it with something im intrested in. Anyway my "App" is supposed to be seperated in two seperate "screens" the top one is only used for displaying stuff and the all interactive stuff is controlled from the bottom "screen".
Now i want to display some text in old school way by getting it written letter by letter to the screen. This is working fine but for some reason the Label widget is only updated on screen if i call the "print_something" function from the top screen, if i call it from the bottom screen the function is indeed called but the Label widget wont change on screen. Am i doing something wrong?
Here is a stripped version of the code:
from kivy.app import App
from kivy.lang import Builder
from kivy.properties import ObjectProperty
from kivy.core.window import Window
from kivy.uix.widget import Widget
from kivy.clock import Clock
Builder.load_string('''
<MainUI>:
orientation: 'vertical'
# both these variables can be the same name and this doesn't lead to
# an issue with uniqueness as the id is only accessible in kv.
<Screen1>:
print_txt: print_txt
layout: layout
RelativeLayout:
id: layout
pos: 0, 400
size: 480, 400
Button:
pos: 0, 200
size_hint: (1, 0.2)
text: "Test Print"
on_press: root.print_something('TEST PRINT FROM SCREEN1')
AnchorLayout:
anchor_x: 'center'
anchor_y: 'bottom'
Label:
id: print_txt
padding_x: 10
markup: True
text_size: self.size
halign: 'left'
valign: 'top'
size_hint: (1, 0.2)
text: ""
<Screen2>:
btn1: btn1
RelativeLayout:
pos: 0, 0
size: 480, 400
Button:
id: btn1
pos_hint: {'x': .15, 'center_y': .5}
size_hint: (0.7, 0.5)
text: "Test Print"
on_press: root.print_text()
''')
class Screen1(Widget):
print_txt = ObjectProperty(None)
layout = ObjectProperty(None)
def print_something(self, string):
print 'Function called...'
self.print_txt.text = ''
counter = [0]
string_len = len(string)
def print_step(dt):
if counter[0] == string_len:
return False
else:
self.print_txt.text += string[counter[0]]
counter[0] = counter[0] + 1
Clock.schedule_interval(print_step, 2.0/60.0)
print 'Function End..'
class Screen2(Widget):
btn1 = ObjectProperty(None)
def __init__(self):
super(Screen2, self).__init__()
def print_text(self):
print 'Trying to print Text from Screen2 to Screen1'
target = Screen1()
target.print_something('TEST PRINT FROM SCREEN2')
class MainUI(Widget):
def __init__(self):
super(MainUI, self).__init__()
self.screen1 = Screen1()
self.add_widget(self.screen1)
self.add_widget(Screen2())
class MainApp(App):
def build(self):
Window.size = (480, 800)
return MainUI()
if __name__ == '__main__':
MainApp().run()
回答1:
Your Screen2 print_text method creates a new Screen1 instance, which is modified but not displayed anywhere so you don't see anything change.
You could change the call to instead something like
on_press: root.parent.screen1.print_text()
...to access the print_text function of the Screen1 instance that you actually want to update.
来源:https://stackoverflow.com/questions/33576913/kivy-modifying-a-child-widget-of-another-separate-class