问题
I am trying to serve static files that I have in a package_docs directory. When I open in the browzer:
http://127.0.0.1:8001/packages/docs/index.html , the page is running.
But I want to open the page: http://127.0.0.1:8001/packages/docs/
without the source file. And the output is 404 Not Found
app.mount("/packages/docs",
StaticFiles(directory=pkg_resources.resource_filename(__name__, 'package_docs')
),
name="package_docs")
@app.get("/packages/docs/.*", include_in_schema=False)
def root():
return HTMLResponse(pkg_resources.resource_string(__name__, "package_docs/index.html"))
app.include_router(static.router)
app.include_router(jamcam.router, prefix="/api/v1/cams", tags=["jamcam"])
How can I change my code? Any advice will be helpful. Thank you in advance.
回答1:
You need to use FastAPI's TemplateResponse
(actually Starlette's):
from fastapi import Request
from fastapi.staticfiles import StaticFiles
from fastapi.templating import Jinja2Templates
app.mount("/static", StaticFiles(directory="static"), name="static")
templates = Jinja2Templates(directory="package_docs")
@app.get("/items/{id}")
async def example(request: Request):
return templates.TemplateResponse("index.html", {"request": request})
Request
as part of the key-value pairs in the context for Jinja2. So, you also have to declare it as query parameter. and you have to specify a html file you want to render it with Jinja ("your.html", {"request": request})
Also to return a HTMLResponse directly you can use HTMLResponse
from fastapi.responses
from fastapi.responses import HTMLResponse
@app.get("/items/", response_class=HTMLResponse)
async def read_items():
return """
<html>
<head>
<title></title>
</head>
<body>
</body>
</html>
"""
You can read more about custom response from FastAPI Custom Responses
回答2:
There's a html option in Starlette that can be used within FastAPI. Starlette Documentation
This would let you have something such as:
app.mount("/site", StaticFiles(directory="site", html = True), name="site")
Which would parse /site to /site/index.html, /site/foo/ to /site/foo/index.html, etc.
The other answers can help you redirect if you want to change the folder names in a way not handled by using "directory = /foo", but this is the simplest option if you simply want to load the associated .html files.
回答3:
From the docs
The first "/static" refers to the sub-path this "sub-application" will be "mounted" on. So, any path that starts with "/static" will be handled by it.
This means that you mount your directory at http://127.0.0.1:8001/packages/docs/ , but you then need to either specify a file in the URL, or add a handler as you did. The problem though, is that since you mounted the path first, it will not take into consideration the following paths that include part of the path.
A possibility is to first specify the path for http://127.0.0.1:8001/packages/docs/ so that it is handled by fastapi and then to mount the folder, serving static files.
Also, I would redirect users asking for http://127.0.0.1:8001/packages/docs/ to http://127.0.0.1:8001/packages/docs/index.html
回答4:
If app.mount
is not an option,
you can always manually read the file and respond with its content...
For example, if your static files are inside /site
then:
from os.path import isfile
from fastapi import Response
from mimetypes import guess_type
@app.get("/site/{filename}")
async def get_site(filename):
filename = './site/' + filename
if not isfile(filename):
return Response(status_code=404)
with open(filename) as f:
content = f.read()
content_type, _ = guess_type(filename)
return Response(content, media_type=content_type)
@app.get("/site/")
async def get_site_default_filename():
return await get_site('index.html')
来源:https://stackoverflow.com/questions/62455652/how-to-serve-static-files-in-fastapi