How to describe strings ending with one or two numbers in one LIKE pattern?

问题

When I am searching for a string ending with one or two numbers, I am using the following pattern:

WHERE MyString LIKE 'ABC[0-9]'
OR MyString LIKE 'ABC[0-9][0-9]'

Is there a way to express my intent in one single equivalent pattern?

回答1:

If LIKE supported regex quantifier syntax, you would do:

LIKE 'ABC[0-9]{1,2}'

However, according to the spec it does not.

If you do not want to use the regular expression functions, then you are stuck with what you have.

回答2:

You can use regular expressions with SQLServer.

Then your expression will become something like:

where dbo.RegexMatch( MyString, N'^ABC[0-9]{1,2}$' )

回答3:

One way, although there is not much wrong with the 2 ORs (Remove '??' + to skip values that are just 1 or 2 digits)

;with T(f) as (
    select 'xxxxxxxxx' union
    select 'xxxxxxxx6' union
    select 'xxxxxxx66' union
    select 'xxxxxx666' union
    select 'xxxxx6666' union 
    select 'xxxxx666x' union
    select '66' union
    select '6' union
    select ''
)
select 
    *
from 
    T
where 
    patindex('%[^0-9]%', reverse(right('??' + f, 3))) > 1

>>

f
6
66
xxxxxxx66
xxxxxxxx6

回答4:

How about something like this?

WHERE SUBSTRING(MyString, 4, 2) NOT LIKE '%[^0-9]%'

来源：https://stackoverflow.com/questions/8478775/how-to-describe-strings-ending-with-one-or-two-numbers-in-one-like-pattern