问题
Here is my data finger table, [dbo].[tFPLog]
CardID Date Time TransactionCode
100 2020-09-01 08:00 IN
100 2020-09-01 17:00 OUT
100 2020-09-01 17:10 OUT
200 2020-09-01 16:00 IN
200 2020-09-02 02:00 OUT
200 2020-09-02 02:15 OUT
100 2020-09-02 07:00 IN
100 2020-09-02 16:00 OUT
200 2020-09-02 09:55 IN
200 2020-09-02 10:00 IN
200 2020-09-02 21:00 OUT
Conditions
- Assume Employees will be IN and OUT in same day/next day.
- Assume There will be multiple IN and OUT for same day/next day for employees. So need first IN and Last Out.
- Duration = (FirstInTime - LastOutTime)
The current result i get using the query:
WITH CTE AS(
SELECT CardID,
[Date] AS DateIn,
MIN(CASE TransactionCode WHEN 'In' THEN [time] ELSE '23:59:59.999' END) AS TimeIn, --'23:59:59.999' as we are after the MIN, and NULL is the lowest value
[Date] AS DateOut,
MAX(CASE TransactionCode WHEN 'Out' THEN [time] END) AS TimeOut
FROM YourTable
GROUP BY CardID, [Date])
SELECT C.DateIn,
C.TimeIn,
C.DateOut,
C.TimeOut,
DATEADD(MINUTE,DATEDIFF(MINUTE,C.TimeIn,C.TimeOut),CONVERT(time(0),'00:00:00')) AS Duration
FROM CTE C;
=====The Current Result======
CardID DateIN TimeIN DateOUT TimeOUT Duration
100 2020-09-01 08:00 2020-09-01 17:10 09:10
200 2020-09-01 16:00 ? ? ?
100 2020-09-02 07:00 2020-09-02 16:00 09:00
200 2020-09-02 09:55 2020-09-02 21:00 11:05
=====The Result Needed===== I want this result.
CardID DateIN TimeIN DateOUT TimeOUT Duration
100 2020-09-01 08:00 2020-09-01 17:10 09:10
200 2020-09-01 16:00 2020-09-02 02:15 10:15
100 2020-09-02 07:00 2020-09-02 16:00 09:00
200 2020-09-02 09:55 2020-09-02 21:00 11:05
How to get the DateOUT and TimeOUT in the nextday? with the condition FIRST IN AND LAST OUT. Please help, thank you in advance.
回答1:
This seems like you were really overly complicating the problem. Just use some conditional aggregation, and then get the difference in minutes:
WITH CTE AS(
SELECT CardID,
[Date] AS DateIn,
MIN(CASE TransactionCode WHEN 'In' THEN [time] ELSE '23:59:59.999' END) AS TimeIn, --'23:59:59.999' as we are after the MIN, and NULL is the lowest value
[Date] AS DateOut,
MAX(CASE TransactionCode WHEN 'Out' THEN [time] END) AS TimeOut
FROM YourTable
GROUP BY CardID, [Date])
SELECT C.DateIn,
C.TimeIn,
C.DateOut,
C.TimeOut,
DATEADD(MINUTE,DATEDIFF(MINUTE,C.TimeIn,C.TimeOut),CONVERT(time(0),'00:00:00')) AS Duration
FROM CTE C;
This assumes that [date] is a date and [time] is a time (because, after all, that is what they are called...).
Side Note: it seems some what redundant have a DateIn and DateOut column when they will always have the same value. Might as well just have a [Date] Column.
Or perhaps, you are actually after this?
WITH CTE AS(
SELECT CardID,
[Date] AS DateIn,
[Time] AS TimeIn,
LEAD([Date]) OVER (PARTITION BY CardID ORDER BY [Date], [Time]) AS DateOut,
LEAD([Time]) OVER (PARTITION BY CardID ORDER BY [Date], [Time]) AS TimeOut,
TransactionCode
FROM dbo.YourTable)
SELECT C.DateIn,
C.TimeIn,
C.DateOut,
C.TimeOut
FROM CTE C
WHERE TransactionCode = 'IN';
Note that if that is the case, you would actually be better off storing the values [date] and [time] in a single column as a datetime/datetime2, not separate ones; as the values are clearly not distinct from each other.
Based on the (hopefully) final goal posts:
WITH VTE AS(
SELECT *
FROM (VALUES(100,CONVERT(date,'20200901'),CONVERT(time(0),'08:00:00'),'IN'),
(100,CONVERT(date,'20200901'),CONVERT(time(0),'17:00:00'),'OUT'),
(100,CONVERT(date,'20200901'),CONVERT(time(0),'17:10:00'),'OUT'),
(200,CONVERT(date,'20200901'),CONVERT(time(0),'16:00:00'),'IN'),
(200,CONVERT(date,'20200902'),CONVERT(time(0),'02:00:00'),'OUT'),
(200,CONVERT(date,'20200902'),CONVERT(time(0),'02:15:00'),'OUT'),
(100,CONVERT(date,'20200902'),CONVERT(time(0),'07:00:00'),'IN'),
(100,CONVERT(date,'20200902'),CONVERT(time(0),'16:00:00'),'OUT'),
(200,CONVERT(date,'20200902'),CONVERT(time(0),'09:55:00'),'IN'),
(200,CONVERT(date,'20200902'),CONVERT(time(0),'10:00:00'),'IN'),
(200,CONVERT(date,'20200902'),CONVERT(time(0),'21:00:00'),'OUT'))V(CardID,[Date],[Time],TransactionCode)),
Changes AS(
SELECT CardID,
DATEADD(MINUTE,DATEDIFF(MINUTE, '00:00:00',[time]),CONVERT(datetime2(0),[date])) AS Dt2, --Way easier to work with later
TransactionCode,
CASE TransactionCode WHEN LEAD(TransactionCode) OVER (PARTITION BY CardID ORDER BY [Date],[Time]) THEN 0 ELSE 1 END AS CodeChange
FROM VTE V),
Groups AS(
SELECT CardID,
dt2,
TransactionCode,
ISNULL(SUM(CodeChange) OVER (PARTITION BY CardID ORDER BY dt2 ROWS BETWEEN UNBOUNDED PRECEDING AND 1 PRECEDING),0) AS Grp
FROM Changes),
MinMax AS(
SELECT CardID,
TransactionCode,
CASE TransactionCode WHEN 'IN' THEN MIN(dt2) WHEN 'Out' THEN MAX(dt2) END AS GrpDt2
FROM Groups
GROUP BY CardID,
TransactionCode,
Grp),
--And now original Logic
CTE AS(
SELECT CardID,
GrpDt2 AS DatetimeIn,
LEAD([GrpDt2]) OVER (PARTITION BY CardID ORDER BY GrpDt2) AS DateTimeOut,
TransactionCode
FROM MinMax)
SELECT C.CardID,
CONVERT(date,DatetimeIn) AS DateIn,
CONVERT(time(0),DatetimeIn) AS TimeIn,
CONVERT(date,DatetimeOut) AS DateOtt,
CONVERT(time(0),DatetimeOut) AS TimeOut,
DATEADD(MINUTE, DATEDIFF(MINUTE,DatetimeIn, DateTimeOut), CONVERT(time(0),'00:00:00')) AS Duration
FROM CTE C
WHERE TransactionCode = 'IN';
来源：https://stackoverflow.com/questions/63905630/select-first-in-and-last-out-time-different-date-from-data-finger