问题
Hello I'm using inherited controllers. These are my controllers:
-baseAdminController:
<?php
if (!defined('BASEPATH'))
exit('No direct script access allowed');
class _BaseAdminController extends CI_Controller {
public function __construct() {
parent::__construct();
$this->load->library('session');
$calledFunction= $this->router->fetch_method();
if ($calledFunction!= 'loginView' && $calledFunction!= 'doLogin') {
$this->checkSession();
}
}
public function checkSession() {
if ($this->session->userdata('loggedIn') == false) {
$this->load->view('admin/loginView');
}
}
}
And my derived Admin Controllers:
if (!defined('BASEPATH'))
exit('No direct script access allowed');
class AdminController extends _BaseAdminController {
public function indexView() {
$this->load->view('admin/indexView');
}
}
When i'm tring to login, CodeIgniter shows me both admin/loginView and admin/indexView. Because i'm checking session status at constructing my derived controller. How can i prevent to loading second view?
Thank in advance..
回答1:
To answer your question, you could have done the following into your checkSession method:
public function checkSession() {
if ($this->session->userdata('loggedIn') == false) {
echo $this->load->view('admin/loginView', array(), TRUE);
exit;
}
}
Explanation: If you pass the third argument as TRUE, it will return the content of that file. Read ellislab.com for more info.
回答2:
I hope this is related to your question:
I recently wanted to have a bunch of controllers extend a parent controller class (MY_Acl_Controller) that checked that the current logged-in user deserved access to each method (using a homegrown ACL library). The check was to be initiated in MY_Acl_Controller's constructor, so it would run on every request.
I wanted to set the Output class's output to the result of loading a view, then display the view and exit, but because this process was NOT executed in a routed controller method, I couldn't just call $this->load->view('errors/access_denied') and then return from the constructor function... CI would then carry on executing controller code.
So I created a MY_Output class, extending CI_Output, and added to it a public function display_with_exit():
public function display_with_exit()
{
$this->_display($this->final_output);
exit;
}
Then, in MY_Acl_Controller's constructor:
...
if(!$user_deserves_access)
{
$this->load->view('errors/access_denied');
$this->output->display_with_exit();
}
Maybe that might be useful to someone?
The advantage of this approach is that the Output class's _display() function sends all HTTP headers you'd like it to, as per any normal response.
回答3:
Avoid exit;
/ function exit;
or die;
will terminate execution, its better practice in only debugging your code.
Try like below.
public function index(){
if($xx) return TRUE;
}
来源:https://stackoverflow.com/questions/17225251/forcing-codeigniter-to-send-view-and-stop-working