How do I fix this: Use of undefined constant slug - assumed 'slug'

问题

I took my HTML website and turned it into a PHP site. I'm in the testing phase currently however, I keep getting "Notices" on the rendered page instead of content.

I've tried turning the constants to variables with $, but the notice still appears. However, it changed from undefined constant to undefined variable. I changed them back to constants.

I'm on a WinXP 32-bit, therefore, I use Xammp 1.8.2 with PHP 5.4.31

the array in question:

    $navItems = array(
                      array(
                              slug => "index.php",
                              title => "Home"
                            ),
                      array(
                              slug => "about.php",
                              title => "About Me"
                            ),
                      array(
                              slug => "portfolio.php",
                              title => "Portfolio"
                            ),
                      array(
                              slug => "contact.php",
                              title => "Contact"
                            )
        );

I am expecting to see the actual page content. However, I get:

Notice: Use of undefined constant slug - assumed 'slug' in C:\xampp\htdocs\zmglobal-it.com.php\includes\arrays.php on line 5

Notice: Use of undefined constant title - assumed 'title' in C:\xampp\htdocs\zmglobal-it.com.php\includes\arrays.php on line 6

回答1:

Your array looks great, you might just want to slightly modify it, and add " or ' in some places that are required, for example like:

$navItems = array(
    array(
        "slug" => "index.php",
        "title" => "Home",
    ),
    array(
        "slug" => "about.php",
        "title" => "About Me",
    ),
    array(
        "slug" => "portfolio.php",
        "title" => "Portfolio",
    ),
    array(
        "slug" => "contact.php",
        "title" => "Contact",
    ),
);

or maybe:

$navItems = [
    [
        "slug" => "index.php",
        "title" => "Home",
    ],
    [
        "slug" => "about.php",
        "title" => "About Me",
    ],
    [
        "slug" => "portfolio.php",
        "title" => "Portfolio",
    ],
    [
        "slug" => "contact.php",
        "title" => "Contact",
    ],
];

var_dump($navItems);

Output

This is the output of var_dump($navItems);:

array(4) {
  [0]=>
  array(2) {
    ["slug"]=>
    string(9) "index.php"
    ["title"]=>
    string(4) "Home"
  }
  [1]=>
  array(2) {
    ["slug"]=>
    string(9) "about.php"
    ["title"]=>
    string(8) "About Me"
  }
  [2]=>
  array(2) {
    ["slug"]=>
    string(13) "portfolio.php"
    ["title"]=>
    string(9) "Portfolio"
  }
  [3]=>
  array(2) {
    ["slug"]=>
    string(11) "contact.php"
    ["title"]=>
    string(7) "Contact"
  }
}

Reference 1

What does the PHP error message “Notice: Use of undefined constant” mean?

回答2:

Key values must be quoted so use "keyname" or 'keyname'

''' { $navItems = array( array( "slug" => "index.php", "title" => "Home", ), array( "slug" => "about.php", "title" => "About Me", ), array( "slug" => "portfolio.php", "title" => "Portfolio", ), array( "slug" => "contact.php", "title" => "Contact", ) ); } '''

来源：https://stackoverflow.com/questions/56316101/how-do-i-fix-this-use-of-undefined-constant-slug-assumed-slug

标签

php

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