Match unescaped quotes in quoted csv

问题

I've looked at several of the Stack Overflow posts with similar titles, and none of the accepted answers have done the trick for me.

I have a CSV file where each "cell" of data is delimited by a comma and is quoted (including numbers). Each line ends with a new line character.

Some text "cells" have quotation marks in them, and I want to use regex to find these, so that I can escape them properly.

Example line:

"0","0.23432","234.232342","data here dsfsd hfsdf","3/1/2016",,"etc","E 60"","AD"8"\n

I want to match just the " in E 60" and in AD"8, but not any of the other ".

What is a (preferably Python-friendly) regular expression that I can use to do this?

回答1:

EDIT: Updated with regex from @sundance to avoid beginning of line and newline.

You could try substituting only quotes that aren't next to a comma, start of line, or newline:

import re

newline = re.sub(r'(?<!^)(?<!,)"(?!,|$)', '', line)

回答2:

Rather than using regex, here's an approach that uses Python's string functions to find and escape only quotes between the left and rightmost quotes of a string.

It uses the .find() and .rfind() methods of strings to find the surrounding " characters. It then does a replacement on any additional " characters that appear inside the outer quotes. Doing it this way makes no assumptions about where the surrounding quotes are between the , separators, so it will leave any surrounding whitespace unaltered (for example, it leaves the '\n' at the end of each line as-is).

def escape_internal_quotes(item):
    left = item.find('"') + 1
    right = item.rfind('"')
    if left < right:
        # only do the substitution if two surrounding quotes are found
        item = item[:left] + item[left:right].replace('"', '\\"') + item[right:]
    return item

line = '"0","0.23432","234.232342","data here dsfsd hfsdf","3/1/2016",,"etc","E 60"","AD"8"\n'
escaped = [escape_internal_quotes(item) for item in line.split(',')]
print(repr(','.join(escaped)))

Resulting in:

'"0","0.23432","234.232342","data here dsfsd hfsdf","3/1/2016",,"etc","E 60\\"","AD\\"8"\n'

来源：https://stackoverflow.com/questions/43623701/match-unescaped-quotes-in-quoted-csv

标签

python

regex

csv

regex-lookarounds