Compare elements of two arrays in less than O(n^2) time?

问题

I have two integer arrays. I need to find out two numbers, one from each array, whose sum is equal to 2. This is very simple in O(n^2) but is there a way to do it faster?

回答1:

You can do it in O(N+M) time and O(N) space like this:

• Put elements of array a into a hash set
• Walk through array b, and check if hash table contains 2-b[i]

Constructing a hash set of N elements takes O(N) time and O(N) space. Checking each of M elements against the hash set takes O(1), for a total of O(N+M) time.

来源：https://stackoverflow.com/questions/49407831/compare-elements-of-two-arrays-in-less-than-on2-time