How to solve 'x' must be numeric in r?

问题

I'm trying to make a histogram but I keep running into the an error message. Here is my code

library(readxl)

data <- read_excel("data.xls")

View(data)
attach(data)
names(data)        

hist(data)

This is my sample. I want to create a histogram the y-axis be 0-100, x-axis (safely, basic, limited, etc) the numbers (39,29,8,12,12) be in the graph. Does this help make sense?

   Safely  Basic  Limited  Unimproved  Open

   39     29         8          12      12

Error in hist.default(data) : 'x' must be numeric

What am I doing wrong? I don't know understand the error message.

回答1:

The issue is that you are passing a dataframe to the hist() function, when it requires a vector for its argument x (see ?hist). Based on your edited post, you would want:

hist(as.numeric(data[1,]))

Where data[1,] creates a vector from the first row of your dataframe.

Though it seems like you may actually be looking for a bar plot. In that case, try:

plot_data <- data.frame(t(data)) %>% 
  tibble::rownames_to_column()

ggplot(plot_data,aes(x = rowname,y=t.data.)) + 
  stat_identity(geom = "bar")

From @user2554330, a simpler base graphics method:

f <- as.numeric(data[1,])
names(f) <- names(data)
barplot(f)

回答2:

In your case data is not a variable, but a dataframe that contains variables. You can take the histogram of each single variable like this:

library(readxl)
data <- read_excel("data.xls")

If you want to look at the histogram of variable Safely:

hist(data$Safely)

You can access each variable contained in data in the same way.

来源：https://stackoverflow.com/questions/55592116/how-to-solve-x-must-be-numeric-in-r

标签

histogram

numeric