问题
in my code i've create a modificator and generate the column chiave_composita. If i run this code i've obtain the data
TransazioniOrigine::all()->pluck('chiave_composita')->toArray()
but if i use this code
$origine = TransazioniOrigine::all()->pluck('chiave_composita')->toArray();
$destinazione = Transazioni::all()->pluck('transazioneKey')->toArray();
$diff = array_diff($origine, $destinazione);
dd(TransazioniOrigine::whereIn('chiave_composita', $diff)->get());
i have this errror:
Il nome di colonna 'chiave_composita' non è valido. (SQL: select * from [vwTransazioni] where [chiave_composita] in (1515152021011110))
how can i solve this issues?
Thanks
回答1:
You can't use whereIn
with accessors. The database doesn't know about them.
What you can do is filter
the resulting collection.
TransazioniOrigine::get()->filter(fn($t) => in_array($t->chiave_composita, $diff));
回答2:
THanks IGP!!! With your suggestion i've solved the problem.
来源:https://stackoverflow.com/questions/65675483/eloquent-use-a-modificator-in-wherein