问题
I have been working with a comparable class that runs and compares correctly, but when I try to print the values out, it gives me the memory addresses. I know that this could be fixed with a toString
method, but I'm not really sure how to go about doing so. Here's my code:
import java.io.*;
import java.util.*;
import java.lang.Object;
public class StreetAddress implements Comparable<StreetAddress>
{
protected int num;
protected String stName;
public StreetAddress(int n, String s){
num = n;
stName = s;
}
public int getNum(){
// returns the street number
return num;
}
public String getName(){
// returns the street name
return stName;
}
public int compareTo(StreetAddress street) throws ClassCastException{
// exception prevents crash if an address is not compared to
// another address
int compareName = this.stName.compareTo(street.stName);
int compareNum = this.num - street.num;
if (compareName < 0){
// first address comes after compared address
return compareName;
}
else if (compareName == 0){ // same address name
if (compareNum < 0){
System.out.println(this.num + "" + this.stName + ", " + street.num + "" + street.stName);
return compareName;
}
else{
System.out.println("");
return compareName;
}
}
else{
// first address comes before compared address
return compareName;
}
}
public static void main(String args[])
{
StreetAddress add1 = new StreetAddress(7864, "cartesian road");
StreetAddress add2 = new StreetAddress(5141, "cartesian road");
StreetAddress add3 = new StreetAddress(1664, "n kings street");
StreetAddress add4 = new StreetAddress(9753, "pioneer parkway");
StreetAddress add5 = new StreetAddress(3643, "starry avenue");
add1.compareTo(add2);
add4.compareTo(add1);
add3.compareTo(add3);
add2.compareTo(add5);
}
}
回答1:
Simple:
@Override
public String toString() {
return String.format("%d %s", num, stName);
}
The @Override
annotation is not necessary but it is definately good practice. Note that String.format("%d %s", num, stName)
results in a string of the form "[num] [street]"
. I find that String.format gives greater flexibility than string concatenation if you want to make changes in the future.
回答2:
@Override
public String toString() {
return "StreetAddress: num= " + num + ", stName=" + stName ;
}
来源:https://stackoverflow.com/questions/15868959/returning-a-string-with-tostring-java