问题
I want to create a random list with 100 elements. So far, so good...
Example 1: works fine, because the function has a range which is big enough not to repeat any value
list = random.sample(range(1,200),100)
Example 2: Does not work, because the range is too small (sample is larger than population)
list = random.sample(range(50,80),100)
I am looking for a way to create that random list with more values than the range and it is no problem that the elements exists several times.
回答1:
In this case, do not use random.sample, but build the list from elements chosen within a range:
import random
[random.randrange(50, 80) for _ in range(100)]
example output:
[57,
52,
59,
67,
52, # some elements repeat
64,
75,
...
回答2:
Use numpy random:
import numpy as np
np.random.randint(low=3,high=12,size=100)
回答3:
Have a look at numpy.choice
import numpy as np
l = range(50,80)
np.random.choice(l, 100, True)
回答4:
Use list comprehension + randint,
[random.randint(1,200) for _ in range(100)]
See the element are repeating the count is not 100,
In [6]: len(set([random.randint(1,200) for _ in range(100)]))
Out[6]: 76
来源：https://stackoverflow.com/questions/46969675/how-to-create-a-random-list-with-only-unique-values