Regex to match strings inside brackets with no spaces around

问题

I'm using the following regex to match strings inside brackets:

\((.*?)\)

But this matches this:

(word)

and this too:

( word )

I need to modify it to only match the first case: words inside brackets with no spaces around: (word)

Any ideas?

Thanks in advance

回答1:

Use lookahead/lookbehind to disallow space after the opening parenthesis and before the closing parenthesis:

\((?!\s)[^()]+(?<!\s)\)

(?!\s) and (?<!\s) mean "not followed by / not preceded by a space".

The part in the middle, [^()]+ requires one or more characters to be present between parentheses, disallowing () match.

Demo.

回答2:

You can use this pattern:

\([^\s()](?:[^()]*[^\s()])?\)

[^\s()] ensures that the first character isn't a whitespace or brackets (and make mandatory at least one character).

(?: [^()]* [^\s()] )? is optional. if it matches, the same character class ensures that the last character isn't a whitespace.

回答3:

• Word Boundaries

\(\b[^)]+\b\)

来源：https://stackoverflow.com/questions/46262902/regex-to-match-strings-inside-brackets-with-no-spaces-around