python input() EOF error and return value of type int?

问题

I have 2 questions on these 2 short codes.

1.

name = input('what: ')
print(name)

output

what: 641u
Traceback (most recent call last):
  File "/Users/vuthynun/PycharmProjects/untitled1/h/__init__.py", line 1, in <module>
    name = input('what: ')
  File "<string>", line 1
    641u
       ^
SyntaxError: unexpected EOF while parsing

Process finished with exit code 1

Why does it give me this error?

2.

name = input('what: ')

print(type(name))

output:

what: 23
<type 'int'>

Process finished with exit code 0

Why is name type int? I thought all input are converted to string.

Please please please help me understand this. It's killing me.

回答1:

Use raw_input instead of input in python 2. That's how you get strings. Otherwise python will evaluate what you give it, which is giving you your unexpected behaviour.

回答2:

This is the behavior in Python 2.7. Whatever you accept via input will be converted to type int and whatever you accept via raw_input, will be converted to type str.

For behavior in Python 3, check this: What's the difference between raw_input() and input() in python3.x?

来源：https://stackoverflow.com/questions/46292743/python-input-eof-error-and-return-value-of-type-int