问题
import java.util.*;
public class Prac9FibonacciNumbers {
public static void main(String[] args) {
int[] x = new int[100];
x[0] = 1;
x[1] = 1;
for (int a = 2; a < 100; a++) {
x[a] = x[a - 1] + x[a - 2];
}
for (int a = 0; a < 100; a++) {
if(a < 99){
System.out.print(x[a] + ",");
}
else{
System.out.print(x[a]);
}
}
}
}
This program is meant to create a list of Fibonacci numbers. However, for some reason, it is giving me negative numbers right in the middle of my output.
I could use
Math.abs()
but I want to know why it is giving me negative numbers. The output is down below. Please help me with understanding this problem.
1,1,2,3,5,8,13,21,34,55,89,144,233,377,610,987,1597,2584,4181,6765,10946,17711,28657,46368,75025,121393,196418,317811,514229,832040,1346269,2178309,3524578,5702887,9227465,14930352,24157817,39088169,63245986,102334155,165580141,267914296,433494437,701408733,1134903170,1836311903,-1323752223,512559680,-811192543,-298632863,-1109825406,-1408458269,1776683621,368225352,2144908973,-1781832971,363076002,-1418756969,-1055680967,1820529360,764848393,-1709589543,-944741150,1640636603,695895453,-1958435240,-1262539787,1073992269,-188547518,885444751,696897233,1582341984,-2015728079,-433386095,1845853122,1412467027,-1036647147,375819880,-660827267,-285007387,-945834654,-1230842041,2118290601,887448560,-1289228135,-401779575,-1691007710,-2092787285,511172301,-1581614984,-1070442683,1642909629,572466946,-2079590721,-1507123775,708252800,-798870975,-90618175,-889489150,-980107325
回答1:
The Fibonacci numbers will grow large quite fast. At the 46th number, you start getting negative numbers, e.g. -1323752223
. This is because the numbers have grown so large that it overflows the int
datatype.
You can use long[]
arrays, but that will only postpone the problem. You'll starting getting negative numbers at the 92nd number, e.g. -6246583658587674878
, because it will overflow the long
datatype.
Using double
won't have the precision needed at this magnitude. You can use BigInteger
s, which have arbitrary precision and magnitude.
BigInteger[] x = new BigInteger[100];
x[0] = BigInteger.ONE;
x[1] = BigInteger.ONE;
And you'll need to use the add
method.
x[a] = x[a - 1].add(x[a - 2]);
回答2:
From the Java Language Specification section on integer operations:
The built-in integer operators do not indicate overflow or underflow in any way. The results are specified by the language and independent of the JVM version: Integer.MAX_VALUE + 1 == Integer.MIN_VALUE and Integer.MIN_VALUE - 1 == Integer.MAX_VALUE. The same goes for the other integer types.
If you do something like this:
int x = 2147483647;
x++;
If you now print out x, it will be the value -2147483648
Use a biginteger datatype to declare your array.
来源:https://stackoverflow.com/questions/30064609/unexpected-negative-numbers-in-java