问题
I want to remove columns from a masked array where every value in the column is masked. So in the following example:
>>> import numpy as np
>>> test = np.array([[1,0,0],[0,3,0],[1,4,0]])
>>> test = np.ma.masked_equal(test,0)
>>> test
[[1 -- --]
[-- 3 --]
[1 4 --]],
>>> np.somefunction(test)
[[1 --]
[-- 3 ]
[1 4 ]]
what should np.somefunction() be to get the given output?
回答1:
You can use fancy indexing:
test[:, ~np.all(test.mask, axis=0)]
#masked_array(data =
# [[1 --]
# [-- 3]
# [1 4]],
# mask =
# [[False True]
# [ True False]
# [False False]],
# fill_value = 0)
回答2:
test[:, ~np.all(test == 0, axis=0)]
回答3:
In [13]: test
Out[13]:
masked_array(data =
[[1 -- --]
[-- 3 --]
[1 4 --]],
mask =
[[False True True]
[ True False True]
[False False True]],
fill_value = 0)
In [14]: test[:, :2]
Out[14]:
masked_array(data =
[[1 --]
[-- 3]
[1 4]],
mask =
[[False True]
[ True False]
[False False]],
fill_value = 0)
来源:https://stackoverflow.com/questions/19380996/remove-columns-where-every-value-is-masked