问题
I defined n-dimensional vectors in Idris as follows:
import Data.Vect
NDVect : (Num t) => (rank : Nat) -> (shape : Vect rank Nat) -> (t : Type) -> Type
NDVect Z [] t = t
NDVect (S n) (x::xs) t = Vect x (NDVect n xs t)
Then I defined the following function which maps a function f to every entry in the tensor.
iterateT : (f : t -> t') -> (v : NDVect r s t) -> NDVect r s t'
iterateT {r = Z} {s = []} f v = f v
iterateT {r = S n} {s = x::xs} f v = map (iterateT f) v
But when I try to call iteratorT
in the following function:
scale : Num t => (c : t) -> (v : NDVect rank shape t) -> NDVect rank shape t
scale c v = iterateT (*c) v
I get the following error message saying there is a type mismatched, which seems pretty fine to me
When checking right hand side of scale with expected type
NDVect rank shape t
When checking argument v to function Main.iterateT:
Type mismatch between
NDVect rank shape t (Type of v)
and
NDVect r s t (Expected type)
Specifically:
Type mismatch between
NDVect rank shape t
and
NDVect r s t
Specifically:
Type mismatch between
NDVect rank shape t
and
NDVect r s t
回答1:
I have also been wondering how to express n-dimensional vectors (i.e. tensors) in Idris. I had a play with the type definition in the question, but encountered various issues, so I expressed the NDVect
function as a data type:
data NDVect : (rank : Nat) -> (shape : Vect rank Nat) -> Type -> Type where
NDVZ : (value : t) -> NDVect Z [] t
NDV : (values : Vect n (NDVect r s t)) -> NDVect (S r) (n::s) t
And implemented map as follows:
nmap : (t -> u) -> (NDVect r s t) -> NDVect r s u
nmap f (NDVZ value) = NDVZ (f value)
nmap f (NDV values) = NDV (map (nmap f) values)
The following now works:
*Main> NDVZ 5
NDVZ 5 : NDVect 0 [] Integer
*Main> nmap (+4) (NDVZ 5)
NDVZ 9 : NDVect 0 [] Integer
*Main> NDV [NDVZ 1, NDVZ 2, NDVZ 3]
NDV [NDVZ 1, NDVZ 2, NDVZ 3] : NDVect 1 [3] Integer
*Main> nmap (+4) (NDV [NDVZ 1, NDVZ 2, NDVZ 3])
NDV [NDVZ 5, NDVZ 6, NDVZ 7] : NDVect 1 [3] Integer
Unfortunately, having all the type constructors makes things a bit ugly. I'd love to know if there's a cleaner way to solve this.
Edit:
Here's a slightly shorter type signature that doesn't explicitly encode the tensor rank in the type:
data NDVect : (shape : List Nat) -> Type -> Type where
NDVZ : (value : t) -> NDVect [] t
NDV : (values : Vect n (NDVect s t)) -> NDVect (n::s) t
nmap : (t -> u) -> (NDVect s t) -> NDVect s u
nmap f (NDVZ value) = NDVZ (f value)
nmap f (NDV values) = NDV (map (nmap f) values)
来源:https://stackoverflow.com/questions/47558158/idris-map-an-operation-on-a-n-dimensional-vector