问题
Consider the following HTML where IDs #p1
, #p2
and #p3
are siblings (see fiddle):
<div id="container">
<span id="p1">Paragraph 1</span>
<span id="p2">Paragraph 2</span>
This is just loose text.
<p id="p3">Paragraph 3</p>
</div>
These are my definitions of strict and loose siblings:
I consider ID
#p1
and#p2
strict siblings (because there is no text which is not encapsulated in any kind of html element between them.And ID
#p2
and#p3
to be loose siblings.
Given any element with a next sibling is it possible to know if the next sibling is strict or loose?
Edit: The siblings may be of different type and I updated the fiddle to reflect that.
回答1:
Answering your question of
Given any element with a next sibling is it possible to know if the next sibling is strict or loose?
rather than following your lead from the fiddle, yes it's possible.
function isMyNextSiblingStrict(element)
{
return ("nodeType" in element && element.nodeType === 1 && element.nextSibling !== null && element.nextSibling.nodeType === 1);
}
This will return true
when an element's next sibling is another element. However, be careful with your example as it is incorrect by your own definition, the two spans have a text node between them made up of white space, so #1 and #2 are not "strict siblings".
<div id="container">
<span id="p1">Paragraph 1</span><!-- WHITESPACE
--><span id="p2">Paragraph 2</span>
This is just loose text.
<p id="p3">Paragraph 3</p>
</div>
These would be "strict siblings".
<div id="container">
<span id="p1">Paragraph 1</span><span id="p2">Paragraph 2</span>
This is just loose text.
<p id="p3">Paragraph 3</p>
</div>
edit - just for fun I've created a jQuery extension that should do what you want - you can see it in your updated jsFiddle, I've not tested it much but it seems to work as you describe
$.fn.extend({
siblingsStrict: function( until, selector ) {
var ret = jQuery.map( this, function( elem ) {
var n = ( elem.parentNode || {} ).firstChild,
r = [],
contig = false;
for ( ; n; n = n.nextSibling ) {
if ( n === elem ) {
contig = true;
}
else if ( n.nodeType === 1 && n !== elem ) {
r.push( n );
}
else if ( n.nodeType === 3 && n.textContent.replace(/\s/g, "") === "" ) {
continue;
}
else if ( n.nodeType === 3 && contig === true ) {
break;
}
else if ( n.nodeType === 3 && contig === false) {
r = [];
}
}
return r;
}, until );
if ( name.slice( -5 ) !== "Until" ) {
selector = until;
}
if ( selector && typeof selector === "string" ) {
ret = jQuery.filter( selector, ret );
}
if ( this.length > 1 ) {
// Remove duplicates
if ( !guaranteedUnique[ name ] ) {
ret = jQuery.unique( ret );
}
// Reverse order for parents* and prev-derivatives
if ( rparentsprev.test( name ) ) {
ret = ret.reverse();
}
}
return this.pushStack( ret );
}
});
回答2:
Is this what you meant: http://cssdeck.com/labs/0blyuslnzv
var isStrict = function(elem1, elem2) {
"use strict";
var e1 = document.querySelectorAll(elem1)[0],
elemNext = document.querySelectorAll(elem1 +" + "+ elem2)[0];
if (e1.nextSibling.textContent.trim().length) {
return e1.nextSibling === elemNext;
} else {
return e1.nextElementSibling === elemNext;
}
};
Usage eg.
isStrict("head", "body") => true
isStrict("#p1", "#p2") => true
isStrict("#p2", "#p3") => false
回答3:
Try this.
var $selector = $("#p1");
$selector.siblings().each(function(){
$(this).addClass('checkSelector');
if(document.querySelectorAll($selector.selector+' + .checkSelector').length){
//Do Strict Action
}else if(document.querySelectorAll($selector.selector+' ~ .checkSelector').length){
//Do non strict but still sibling action
}
$(this).removeClass('checkSelector');
});
http://jsfiddle.net/chsck/5/
回答4:
Ignoring what others might have written;
function checkAdjacency(element1,element2){
var result = isLooseOrStrict(element1,element2);
if(result != 'not'){
return result;
}
else{
return isLooseOrStrict(element2,element1);
}
}
function isLooseOrStrict(elemName1, elemName2){
var element = document.getElementById(elemName1);
var element2 = document.getElementById(elemName2);
if(element.nextSibling.nodeType != 3){
if(element.nextSibling == elem2){
return 'strict';
}
}
else if(element.nextSibling.nextSibling == element2){
if(element.nextSibling.nodeValue.trim() != '')
return 'loose';
else
return 'strict';
}
return 'not';
}
回答5:
you can do this using only vanilla like bellow
(jsFiddle -> http://jsfiddle.net/Castrolol/chsck/4/ )
function getSiblings(elem){
var siblings = [];
var actualElem = elem;
while(actualElem = actualElem.nextSibling ){
if( !actualElem.textContent.trim() ) continue;
siblings.push({
elem: actualElem,
isStrict: !(actualElem instanceof Text)
});
}
return siblings;
}
//using the function
var element = $("#p1").get(0);
var siblings = getSiblings(element);
siblings.forEach(function(sibling){
if( sibling.isStrict ) {
//here is a tag
sibling.elem.style.color = "red";
}else{
//here not is a tag
}
});
来源:https://stackoverflow.com/questions/21761478/how-to-detect-strictly-adjacent-siblings