问题
I have the array:
array = [
{
"id": 1,
"date": {
"id": 1,
"name": "202001"
},
"item": {
"id": 1,
"name": "I1"
},
"price": 100
},
{
"id": 2,
"date": {
"id": 2,
"name": "202002"
},
"item": {
"id": 1,
"name": "I1"
},
"price": 200
},
{
"id": 3,
"date": {
"id": 2,
"name": "202002"
},
"item": {
"id": 2,
"name": "I2"
},
"price": 300
},
]
And I want to be able to display the data as shown in the table:
ITEM | 202001 | 202002 | TOTAL |
---|---|---|---|
I1 | 100 | 200 | 300 |
I2 | - | 300 | 300 |
TOTAL | 100 | 500 | 600 |
I tried
const items_dicc = array.reduce((acc, e) => {
if (!acc[e["item"]["name"]]) {
acc[e["item"]["name"]] = {
[e["date"]["name"]]: e["price"]
}
} else {
acc[e["item"]["name"]][e["date"]["name"]] = e["price"]
}
return acc
}, {})
const dates = [...new Set(Object.keys(items_dicc).map(i => Object.keys(items_dicc[i])).flat())]
to show the values of each date for the same item, now I need the above to calculate the subtotals and the total.
EDIT: Using @sabbir.alam answer
totalSumPerDate = {}; dates.forEach(date => { const sumOnDate = Object.values(items_dicc).reduce((acc, curr) => { acc = acc + (curr[date]? curr[date] : 0); return acc; }, 0); totalSumPerDate[[date]] = sumOnDate; });
totalSum = Object.values(totalSumPerDate).reduce((acc, curr) => acc+curr, 0);
sumPerItem = {}; Object.keys(items_dicc).forEach(key => { const sum = Object.values(items_dicc[key]).reduce((acc, curr) => acc + curr, 0); sumPerItem[[key]] = sum; });
I did
<table>
<thead>
<tr>
<th>ITEM</th>
{dates.map(date => <th>{date}</th>)}
<th>TOTAL</th>
</tr>
</thead>
<tbody>
{
Object.keys(items_dicc).map((item) => {
return (
<tr>
<td>{item}</td>
{dates.map((date) => <td>{items_dicc[item][date] || ''}</td>)}
{Object.values(sumPerItem).map((elem,i) => <td>{elem}</td>)}
</tr>
)
})
}
<tr>
<td>TOTAL</td>
{Object.values(totalSumPerDate).map((elem,i) => <td>{elem}</td>)}
<td>{totalSum}</td>
</tr>
</tbody>
</table>
I need to correct how the side subtotals are displayed.
How can I do it, suggestions?
回答1:
You can do the following using reduce ,
array = [
{
"id": 1,
"date": {
"id": 1,
"name": "202001"
},
"item": {
"id": 1,
"name": "I1"
},
"price": 100
},
{
"id": 2,
"date": {
"id": 2,
"name": "202002"
},
"item": {
"id": 1,
"name": "I1"
},
"price": 200
},
{
"id": 3,
"date": {
"id": 2,
"name": "202002"
},
"item": {
"id": 2,
"name": "I2"
},
"price": 300
},
]
items_dicc = array.reduce((acc, e) => {
if (!acc[e["item"]["name"]]) {
acc[e["item"]["name"]] = {
[e["date"]["name"]]: e["price"]
}
} else {
acc[e["item"]["name"]][e["date"]["name"]] = e["price"]
}
return acc
}, {})
dates = [...new Set(Object.keys(items_dicc).map(i => Object.keys(items_dicc[i])).flat())]
totalSumPerDate = {};
dates.forEach(date => {
const sumOnDate = Object.values(items_dicc).reduce((acc, curr) => {
acc = acc + (curr[date]? curr[date] : 0);
return acc;
}, 0);
totalSumPerDate[[date]] = sumOnDate;
});
totalSum = Object.values(totalSumPerDate).reduce((acc, curr) => acc+curr, 0);
sumPerItem = {};
Object.keys(items_dicc).forEach(key => {
const sum = Object.values(items_dicc[key]).reduce((acc, curr) => acc + curr, 0);
sumPerItem[[key]] = sum;
});
console.log('Sum per item: ', sumPerItem);
console.log('Sum per date: ', totalSumPerDate);
console.log('TotalSum: ', totalSum);
Update for subtotal per item,
<table>
<thead>
<tr>
<th>ITEM</th>
{dates.map(date => <th>{date}</th>)}
<th>TOTAL</th>
</tr>
</thead>
<tbody>
{
Object.keys(items_dicc).map((item) => {
return (
<tr>
<td>{item}</td>
{dates.map((date) => <td>{items_dicc[item][date] || ''}</td>)}
<td>{sumPerItem[item]}</td>
</tr>
)
})
}
<tr>
<td>TOTAL</td>
{Object.values(totalSumPerDate).map((elem,i) => <td>{elem}</td>)}
<td>{totalSum}</td>
</tr>
</tbody>
</table>
来源:https://stackoverflow.com/questions/65388461/how-to-show-the-sum-of-the-values-for-the-same-item-and-for-different-dates-in-r