问题
If a file myfile.py
contains:
class A(object):
# Some implementation
class B (object):
# Some implementation
How can I define a method so that, given myfile.py
, it returns
[A, B]?
Here, the returned values for A and B can be either the name of the classes or the type of the classes.
(i.e. type(A) = type(str) or type(A) = type(type))
回答1:
You can get both:
import importlib, inspect
for name, cls in inspect.getmembers(importlib.import_module("myfile"), inspect.isclass):
you may additionally want to check:
if cls.__module__ == 'myfile'
回答2:
In case it helps someone else. Here is the final solution that I used. This method returns all classes defined in a particular package.
I keep all of the subclasses of X in a particular folder (package) and then, using this method, I can load all the subclasses of X, even if they haven't been imported yet. (If they haven't been imported yet, they cannot be accessible via __all__
; otherwise things would have been much easier).
import importlib, os, inspect
def get_modules_in_package(package_name: str):
files = os.listdir(package_name)
for file in files:
if file not in ['__init__.py', '__pycache__']:
if file[-3:] != '.py':
continue
file_name = file[:-3]
module_name = package_name + '.' + file_name
for name, cls in inspect.getmembers(importlib.import_module(module_name), inspect.isclass):
if cls.__module__ == module_name:
yield cls
回答3:
It's a bit long-winded, but you first need to load the file as a module, then inspect its methods to see which are classes:
import inspect
import importlib.util
# Load the module from file
spec = importlib.util.spec_from_file_location("foo", "foo.py")
foo = importlib.util.module_from_spec(spec)
spec.loader.exec_module(foo)
# Return a list of all attributes of foo which are classes
[x for x in dir(foo) if inspect.isclass(getattr(foo, x))]
来源:https://stackoverflow.com/questions/55067166/in-python-how-do-i-get-the-list-of-classes-defined-within-a-particular-file