问题
In PyPDF2 pdfreader.getNumPages()
gives me the total number of pages of a pdf file.
How can I get this using pdfminer?
回答1:
I hate to just leave a code snippet. For context here is a link to the current pdfminer.six repo where you might be able to learn a little more about the resolve1
method.
As you're working with pdfminer you might print and come across some PDFObjRef
objects. Essentially you can use resolve1
to expand those objects (they're usually a dictionary).
from pdfminer.pdfparser import PDFParser
from pdfminer.pdfdocument import PDFDocument
from pdfminer.pdfpage import PDFPage
from pdfminer.pdfinterp import resolve1
file = open('some_file.pdf', 'rb')
parser = PDFParser(file)
document = PDFDocument(parser)
# This will give you the count of pages
print(resolve1(document.catalog['Pages'])['Count'])
回答2:
Using pdfminer.six you just need to import the high level function extract_pages
, convert the generator into a list and take its lenght.
from pdfminer.high_level import extract_pages
print(len(list(extract_pages(pdf_file))))
回答3:
I found pdfminer very slow in getting total number of pages. Found this a cleaner and faster solution:
pip3 install PyPDF2
from PyPDF2 import PdfFileReader
def get_pdf_page_count(path):
with open(path, 'rb') as fl:
reader = PdfFileReader(fl)
return reader.getNumPages()
回答4:
Using pdfminer
,import
the necessary modules.
from pdfminer.pdfparser import PDFParser
from pdfminer.pdfdocument import PDFDocument
from pdfminer.pdfpage import PDFPage
Create a PDF parser object associated with the file object.
fp = open('your_file.pdf', 'rb')
parser = PDFParser(fp)
Create a PDF document object that stores the document structure.
document = PDFDocument(parser)
Iterate through the create_pages()
function incrementing each time there is a page.
num_pages = 0
for page in PDFPage.create_pages(document):
num_pages += 1
print(num_pages)
来源:https://stackoverflow.com/questions/45841012/how-can-i-get-the-total-count-of-total-pages-of-a-pdf-using-pdfminer-in-python