Session auto logout after inactivity

问题

Is there a built in feature in express session, to enable auto logout after given time of inactivity ? I am using it as below, and want it to logout if session is inactive for half an hour.

app.use(session({
  key: 'sessid',
  secret: 'This is secret',
  resave: true,
  saveUninitialized: true,
  store: new RedisStore(redisOptions),
  cookie: {
    path: '/',
    httpOnly: true,
    secure: false,
    maxAge: 24 * 60 * 60 * 1000,
    signed: false
  }
}))

回答1:

Ok, I'll throw my two cents into the ring here.

Even though it's in theory possible to implement this using rolling session, I don't think you should...

• It would require each user action the send a request to the server, in order for the user not to be logged out.
• You miss an opportunity to inform your user that he/she will be logged out automatically soon (this is what the banks do, for example).
  @Seth did point out in a comment above that there is actually a way to remedy this: "If the front end is separate from the server, you could have client side routing middleware that checks the cookie and visually logs you out, thus proving a good UX."
  I think this is clever, but I also think it's like putting lipstick on a pig.

I believe that the best approach here is to handle this on the client side.

I would suggest something like this:

var AutoLogout = (function() {
  function AutoLogout() {
    this.events = ['load', 'mousemove', 'mousedown',
                   'click', 'scroll', 'keypress'];

    this.warn = this.warn.bind(this);
    this.logout = this.logout.bind(this);
    this.resetTimeout = this.resetTimeout.bind(this);

    var self = this;
    this.events.forEach(function(event) {
      window.addEventListener(event, self.resetTimeout);
    });

    this.setTimeout();
  }

  var _p = AutoLogout.prototype;

  _p.clearTimeout = function() {
    if(this.warnTimeout)
      clearTimeout(this.warnTimeout);

    if(this.logoutTimeout)
      clearTimeout(this.logoutTimeout);
  };

  _p.setTimeout = function() {
    this.warnTimeout = setTimeout(this.warn, 29 * 60 * 1000);

    this.logoutTimeout = setTimeout(this.logout, 30 * 60 * 1000);
  };

  _p.resetTimeout = function() {
    this.clearTimeout();
    this.setTimeout();
  };

  _p.warn = function() {
    alert('You will be logged out automatically in 1 minute.');
  };

  _p.logout = function() {
    // Send a logout request to the API
    console.log('Sending a logout request to the API...');

    this.destroy();  // Cleanup
  };

  _p.destroy = function() {
    this.clearTimeout();

    var self = this;
    this.forEach(function(event) {
      window.removeEventListener(event, self.resetTimeout);
    });
  };

  return AutoLogout;
})();

es2015

class AutoLogout {
  constructor() {
    this.events = ['load', 'mousemove', 'mousedown',
                   'click', 'scroll', 'keypress'];

    this.warn = this.warn.bind(this);
    this.logout = this.logout.bind(this);
    this.resetTimeout = this.resetTimeout.bind(this);

    this.events.forEach((event) => {
      window.addEventListener(event, this.resetTimeout);
    });

    this.setTimeout();
  }

  clearTimeout() {
    if(this.warnTimeout)
      clearTimeout(this.warnTimeout);

    if(this.logoutTimeout)
      clearTimeout(this.logoutTimeout);
  }

  setTimeout() {
    this.warnTimeout = setTimeout(this.warn, 29 * 60 * 1000);

    this.logoutTimeout = setTimeout(this.logout, 30 * 60 * 1000);
  }

  resetTimeout() {
    this.clearTimeout();
    this.setTimeout();
  }

  warn() {
    alert('You will be logged out automatically in 1 minute.');
  }

  logout() {
    // Send a logout request to the API
    console.log('Sending a logout request to the API...');

    this.destroy();  // Cleanup
  }

  destroy() {
    this.clearTimeout();

    this.events.forEach((event) => {
      window.removeEventListener(event, this.resetTimeout);
    });
  }
}

Partial polling solution:

var activityPolling = (function() {
  var events = ['load', 'mousemove', 'mousedown', 'click', 'scroll', 'keypress'];
  var active = true;
  var timeout;

  function poll() {
    if(active) {
      console.log('polling the server...')
    }
  }

  function setIdle() {
    active = false;
  }

  function setActive() {
    active = true;
    if(timeout)
      clearTimeout(timeout);
    timeout = setTimeout(setIdle, 30 * 60 * 1000);
  }

  function destroy() {
    clearInterval(interval);

    events.forEach(function(event) {
      window.removeEventListener(event, setActive);
    });
  }

  events.forEach(function(event) {
    window.addEventListener(event, setActive);
  });

  setActive();

  var interval = setInterval(poll, 60 * 1000);

  return {
    interval: interval,
    destroy: destroy
  }
})();

回答2:

Rolling session may solve the purpose.

If you use the "rolling" option for session to "true," it will update the session timeout on new requests.

What you can do is: set max-age to 5 minutes.

 maxAge: 30*10000

When there is no activity max-age will destroy the session. However, when there is any activity, rolling will renew the session to be alive for next 30 minutes.

Again, the word in-activity in this question is little misleading. In-activity could be any (or all) of no-mouse-movement, no-mouse-click, or no-interaction-with-server.
If you refer inactivity as no-interaction-with-server, this logic will work. However for no-ui-interactions inactivity, you need to handle from client side

来源：https://stackoverflow.com/questions/38143993/session-auto-logout-after-inactivity