问题:
Consider this example (typical in OOP books): 考虑以下示例(OOP书籍中的典型示例):
I have an Animal
class, where each Animal
can have many friends. 我有一个Animal
课,每个Animal
可以有很多朋友。
And subclasses like Dog
, Duck
, Mouse
etc which add specific behavior like bark()
, quack()
etc. 还有子类,如Dog
, Duck
, Mouse
等,它们添加了特定的行为,如bark()
, quack()
等。
Here's the Animal
class: 这是Animal
类:
public class Animal {
private Map<String,Animal> friends = new HashMap<>();
public void addFriend(String name, Animal animal){
friends.put(name,animal);
}
public Animal callFriend(String name){
return friends.get(name);
}
}
And here's some code snippet with lots of typecasting: 这是一些带有大量类型转换的代码片段:
Mouse jerry = new Mouse();
jerry.addFriend("spike", new Dog());
jerry.addFriend("quacker", new Duck());
((Dog) jerry.callFriend("spike")).bark();
((Duck) jerry.callFriend("quacker")).quack();
Is there any way I can use generics for the return type to get rid of the typecasting, so that I can say 有什么办法可以将泛型用于返回类型来摆脱类型转换,所以我可以说
jerry.callFriend("spike").bark();
jerry.callFriend("quacker").quack();
Here's some initial code with return type conveyed to the method as a parameter that's never used. 这是一些带有返回类型的初始代码,这些代码作为从未使用过的参数传递给该方法。
public<T extends Animal> T callFriend(String name, T unusedTypeObj){
return (T)friends.get(name);
}
Is there a way to figure out the return type at runtime without the extra parameter using instanceof
? 有没有一种方法可以使用instanceof
在运行时确定返回类型而无需额外的参数? Or at least by passing a class of the type instead of a dummy instance. 或者至少通过传递类型的类而不是虚拟实例。
I understand generics are for compile time type-checking, but is there a workaround for this? 我了解泛型用于编译时类型检查,但是是否有解决方法?
解决方案:
参考一: https://stackoom.com/question/1tH5/如何使方法返回类型通用参考二: https://oldbug.net/q/1tH5/How-do-I-make-the-method-return-type-generic
来源:oschina
链接:https://my.oschina.net/u/4438370/blog/4282908