public class Foo implements java.io.Serializable {
private int v1;
private static double v2;
private Loan v3 = new Loan();
}
Options:
A. An instance of Foo can be serialized because Foo implements Serializable.
B. An instance of Foo cannot be serialized because Foo contains a non-serializable instance variable v3.
C. If you mark v3 as transient, an instance of Foo is serializable.
D. b and c
Answer: D
Explanation: An object may not be serialized even though its class implements java.io.Serializable
, because it may contain non-serializable instance variables.
Now my question is:
As far as I know, transient is used to turn off serialization. Then how is transient in this case, helping us to serialize foo?
transient
doesn't disable serialization altogether; it just marks members that won't be serialized. It's typically used for stuff that would be incorrect or irrelevant when the object is unserialized, or stuff that it'd be less-than-safe to store (passwords, decrypted data, that sort of thing), or non-serializable stuff that could be easily reconstructed.
In this case, i assume the Loan
class isn't serializable. (If it were, then A would be correct.) Marking v3
as transient just tells Java not to worry about that field, but go ahead and serialize the others. This means an unserialized Foo
might have a null v3
. If you want to store the Loan
as well, you'd need to either keep track of enough info to recreate it at will, or change class Loan
so that it implements java.io.Serializable
as well.
Alternatively, there are methods you could implement (writeObject
, readObject
) if you need control over serialization. But that can be a bit of a hassle.
Then how is transient in this case, helping us to serialize foo?
Because it allows you to serialize the rest of Foo, the other members that are serializable.
First, are you sure that Loan is not serializable? If it is, then B doesn't apply.
On the other hand, if it indeed is not, then B and C are right. transient
doesn't turn off serialization generally, but only for the field with which it's associated. Thus, serializing Foo would not transmit a value for the v3 field. On the receiving end, when re-initializing the Foo instance, the serialization mechanism wouldn't try to read that field from the stream, and would leave it null.
来源:https://stackoverflow.com/questions/5177013/how-does-marking-a-field-as-transient-make-it-possible-to-serialise-an-object