问题
I am practicing with the os
module and more specifically os.walk()
. I am wondering if there is an easier/more efficient way to find the actual path to a file considering this produces a path that suggests the file is in the original folder when os.walk()
is first ran:
import os
threshold_size = 500
for folder, subfolders, files in os.walk(os.getcwd()):
for file in files:
filePath = os.path.abspath(file)
if os.path.getsize(filePath) >= threshold_size:
print filePath, str(os.path.getsize(filePath))+"kB"
This is my current workaround:
import os
threshold_size = 500
for folder, subfolders, files in os.walk(os.getcwd()):
path = os.path.abspath(folder)
for file in files:
filePath = path + "\\" + file
if os.path.getsize(filePath) >= threshold_size:
print filePath, str(os.path.getsize(filePath))+"kB"
For shaktimaan, this:
for folder, subfolders, files in os.walk(os.getcwd()):
for file in files:
filePath = os.path.abspath(file)
print filePath
produces this(most of these files are in a subfolder of projects, not projects itself):
C:\Python27\projects\ps4.py
C:\Python27\projects\ps4_encryption_sol.py
C:\Python27\projects\ps4_recursion_sol.py
C:\Python27\projects\words.txt
C:\Python27\projects\feedparser.py
C:\Python27\projects\feedparser.pyc
C:\Python27\projects\news_gui.py
C:\Python27\projects\news_gui.pyc
C:\Python27\projects\project_util.py
C:\Python27\projects\project_util.pyc
C:\Python27\projects\ps5.py
C:\Python27\projects\ps5.pyc
C:\Python27\projects\ps5_test.py
C:\Python27\projects\test.py
C:\Python27\projects\triggers.txt
C:\Python27\projects\ps6.py
C:\Python27\projects\ps6_pkgtest.py
C:\Python27\projects\ps6_solution.py
C:\Python27\projects\ps6_visualize.py
C:\Python27\projects\ps6_visualize.pyc
C:\Python27\projects\capitalsquiz1.txt
C:\Python27\projects\capitalsquiz2.txt
C:\Python27\projects\capitalsquiz3.txt
C:\Python27\projects\capitalsquiz4.txt
C:\Python27\projects\capitalsquiz5.txt
C:\Python27\projects\capitalsquiz_answers1.txt
C:\Python27\projects\capitalsquiz_answers2.txt
C:\Python27\projects\capitalsquiz_answers3.txt
C:\Python27\projects\capitalsquiz_answers4.txt
C:\Python27\projects\capitalsquiz_answers5.txt
C:\Python27\projects\quiz.py
C:\Python27\projects\file2.txt
C:\Python27\projects\regexes.txt
C:\Python27\projects\regexsearch.py
C:\Python27\projects\testfile.txt
C:\Python27\projects\renamedates.py
回答1:
I think there you mistook what abspath
does. abspath just convert a relative path to a complete absolute filename.
For e.g.
os.path.abspath(os.path.join(r"c:\users\anonymous\", ".."))
#produces this output : c:\users
Without any other information, abspath
can only form an absolute path from the only directory it can know about, for your case the current working directory. So currently what it is doing is it joins os.getcwd()
and your file
So what you would have to do is:
for folder, subfolders, files in os.walk(os.getcwd()):
for file in files:
filePath = os.path.join(os.path.abspath(folder), file)
回答2:
Your work around should work fine, but a simpler way to do this would be:
import os
threshold_size = 500
root = os.getcwd()
root = os.path.abspath(root) # redunant with os.getcwd(), maybe needed otherwise
for folder, subfolders, files in os.walk(root):
for file in files:
filePath = os.path.join(folder, file)
if os.path.getsize(filePath) >= threshold_size:
print filePath, str(os.path.getsize(filePath))+"kB"
The basic idea here is that folder
will be an absolute normalized path if the argument to os.walk
is one and os.path.join
will produce an absolute normalized path if any of the arguments is an absolute path and all the following arguments are normalized.
The reason why os.path.abspath(file)
doesn't work in your first example is that file
is a bare filename like quiz.py
. So when you use abspath
it does essentially the same thing os.path.join(os.getcwd(), file)
would do.
回答3:
This simple example should do the trick. I have stored the result in a list, because for me it's quite handy to pass the list to a different function and execute different operations on a list.
import os
directory = os.getcwd()
list1 = []
for root, subfolders, files in os.walk(directory):
list1.append( [ os.path.join(os.path.abspath(root), elem) for elem in files if elem ])
# clean the list from empty elements
final_list = [ x for x in list1 if x != [] ]
来源:https://stackoverflow.com/questions/30444105/better-way-to-find-absolute-paths-during-os-walk