clip-path:circle() radius doesn't seem to be calculated correctly

问题

It's been bugging me for a while whenever I try to use the CSS circle() function to do some clipping as in:

.red {
  	width: 200px;
        height: 300px;
        background: red;
        border: 2px solid black;
        clip-path: circle(69%);  /*barely cuts off the corners of the .red div */
}

/*  the full circle will enclose the entire box at around 71% or (sqrt(2)/2 * 100%)
 per Mozilla documentation and not at 100% as one might expect */

<div class='red'></div>

the radius never seem to be calculated as I would expect it to. Upon looking into the Mozilla MDN reference (https://developer.mozilla.org/en-US/docs/Web/CSS/basic-shape) it appears they calculate it as follows:

which to me just doesn't seem correct. I would imagine they would calculate the radius of the circumference that encloses the elements rectangle (div, img, etc) as follows:

but that just doesn't seem to be the case. Can anyone shed some light on this. Is this a bug of sorts or am I just not understanding something here?

回答1:

It's defined to be like that, they never meant to calculate the radius you are showing. It's also in the specification.

To better understand let's consider a square. You can have a perfect circle if you consider 50% as value

.red {
  width: 200px;
  height: 200px;
  background: red;
  clip-path: circle(50%);
  border:2px solid;
  box-sizing:border-box;
}

<div class='red'></div>

The idea behind is to consider the following figure:

R is the 'c' you are calculating (the Green lines) and r is the reference used (the puple line). You can easily see that r = R/sqrt(2) and R = sqrt(w² + h²). Combining both will give us:

r = sqrt(w² + h²)/sqrt(2)

Which is the formula you see in the MDN page.

Using 50% of this value inside a square will give us the logical circle:

 r/2 = sqrt(w² + h²)/(2*sqrt(2)) = sqrt(2*w²)/(2*sqrt(2)) = w/2 (or h/2)

To cover the whole square we need a value equal to R/2 which is r/sqrt(2) = r/1.41 and since r is 100% you will have the 71% you discovered

.red {
  width: 200px;
  height: 200px;
  background: red;
  clip-path: circle(calc(100% / 1.44)); /* a little bogger  than 1.4 to better see*/
  border:2px solid;
  box-sizing:border-box;
}

<div class='red'></div>

The same logic apply to a non-square shape where the width and height are different but the reference remain the same:

r = sqrt(w² + h²)/sqrt(2)

From the above we can conclude that the 71% is a magic value that will produce the same output whataver the shape since it rely on the radius of the circumference that encloses the elements rectangle wheraes 50% (or any other value) will give different results:

.red {
  width: 200px;
  height: 200px;
  background: red;
  clip-path: circle(69%); 
  border:2px solid;
  box-sizing:border-box;
}

<div class='red'></div>
<div class='red' style="width:300px;"></div>
<div class='red' style="width:100px;"></div>
<div class='red' style="width:50px;"></div>

Using 50%

.red {
  width: 200px;
  height: 200px;
  background: red;
  clip-path: circle(50%); 
  border:2px solid;
  box-sizing:border-box;
}

<div class='red'></div>
<div class='red' style="width:300px;"></div>
<div class='red' style="width:100px;"></div>
<div class='red' style="width:50px;"></div>

We may also think that any value bigger than 71% is useless since it we will always give a circle bigger than our element. This is true but we should not forget that we have also the position.

Example of output using 100%,200% and even 300%!

.red {
  width: 200px;
  height: 200px;
  background: red;
  border:2px solid;
  box-sizing:border-box;
}

<div class='red' style="clip-path: circle(100% at  0    50%)"></div>

<div class='red' style="clip-path: circle(200% at -100% 50%)"></div>

<div class='red' style="clip-path: circle(300% at -200% 50%)"></div>

I will consider a different property to better clear the confusion which is radial-gradient.

.box {
  width:200px;
  height:200px;
  border:1px solid;
  background:radial-gradient(circle 50%, red ,blue);
}

<div class="box">

</div>

The below code is meant to define a circle with a radius equal to 50% but it's invalid because we don't know the reference:

Note: Percentages are not allowed here; they can only be used to specify the size of an elliptical gradient, not a circular one. This restriction exists because there is are multiple reasonable answers as to which dimension the percentage should be relative to. A future level of this module may provide the ability to size circles with percentages, perhaps with more explicit controls over which dimension is used.^ref

We are dealing with rectangular shapes so we can use the height, the width, the radius you are calculating, etc, etc. A lot of options so they simply decided to make it invalid but for the clip-path they took a decision and defined a reference for the use of percetange.

By the way, you can have better control over your circle considering values like closest-side/farthest-side.

The below will always give us circle touching the closest sides (the same way as contain with background)

.red {
  width: 200px;
  height: 200px;
  background: red;
  clip-path:circle(closest-side); 
  border:2px solid;
  box-sizing:border-box;
}

<div class='red'></div>
<div class='red' style="width:300px;"></div>
<div class='red' style="width:100px;"></div>
<div class='red' style="width:50px;"></div>

The below will always give us circles touching the farthest sides (the same way as cover with background)

.red {
  width: 200px;
  height: 200px;
  background: red;
  clip-path:circle(farthest-side); 
  border:2px solid;
  box-sizing:border-box;
}

<div class='red'></div>
<div class='red' style="width:300px;"></div>
<div class='red' style="width:100px;"></div>
<div class='red' style="width:50px;"></div>

Combined with position they can give some intresting results:

.red {
  width: 200px;
  height: 200px;
  background: red;
  border:2px solid;
  box-sizing:border-box;
  transition:1s all;
}

<div class='red' style="clip-path:circle(farthest-side at left); "></div>
<div class='red' style="clip-path:circle(closest-side at 10% 10%); "></div>
<div class='red' style="clip-path:circle(farthest-side at top left); "></div>
<div class='red' style="clip-path:circle(closest-side at 40% 50%); "></div>

来源：https://stackoverflow.com/questions/59779083/clip-pathcircle-radius-doesnt-seem-to-be-calculated-correctly

标签

css

geometry

clip-path