问题
By using Intel's pin, I printed out the instruction pointer (ip) values for a program with dynamic linking and static linking.
And I've found that their ip values are quite different, even though they are the same program.
A program with static linking shows 0x400f50 for its very first ip value.
but a program with dynamic linking shows 0x7f94f0762090 for its first ip value
I am not sure why they have that quite a large gap.
It would be appreciated if anyone could help me find out the reason
回答1:
I am not sure why they have that quite a large gap.
Because a dynamically linked program does not start executing in the binary: the first few thousands of instructions are executed in the dynamic linker (ld-linux), before control is transferred to _start in the main executable.
See also this answer.
来源：https://stackoverflow.com/questions/62125651/instruction-point-value-of-dynamic-linking-and-static-linking