How to convert dos2unix csv file with python script

问题

I want to convert a csv file into dos2unix format using python in windows. Rightnow I am doing manually by placing csv file in workarea(server) and run command in putty.[Command : dos2unix file_received filename]

回答1:

dos2unix (as I recall) pretty much only strips the trailing linefeeds off each line. So, there's two ways you can do this.

with open(filename, "w") as fout: 
    with open(file_received, "r") as fin:
        for line in fin:
            line = line.replace('\r\n', '\n')
            fout.write(line)

or you can use subprocess to call the UNIX command directly. WARNING: This is bad since you're using a parameter file_received, and people could potentially tag executable commands into it.

import subprocess
subprocess.call([ 'dos2unix', file_received, filename, shell=False])

I haven't tested the above. The shell=False (the default) means a UNIX shell won't be called for the process. This is good to avoid someone inserting commands into the parameters, but you may have to have shell=True in order for the command to work right.

回答2:

The following code would do the trick:

import csv
out_file_path = 
in_file_path = 
with open(out_file_path,'w',newline='') as output_file:
    writer = csv.writer(output_file, dialect=csv.unix_dialect)
    with open(in_file_path,newline='') as input_file:
        reader = csv.reader(input_file)
        for row in reader:
            writer.writerow(row)

来源：https://stackoverflow.com/questions/58363093/how-to-convert-dos2unix-csv-file-with-python-script

标签

python

dos2unix