Convert XML file to csv file format in c#

问题

<?xml version="1.0"?>
<ArrayOfSequence xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
  <Sequence>

    <SourcePath>
      <Point>
        <X>261</X>
        <Y>210</Y>
      </Point>
      <Point>
        <X>261</X>
        <Y>214</Y>
      </Point>
      <Point>
        <X>261</X>
        <Y>227</Y>
      </Point>
      <Point>
        <X>261</X>
        <Y>229</Y>
      </Point>
      <Point>
        <X>261</X>
        <Y>231</Y>
      </Point>
      <Point>
        <X>261</X>
        <Y>234</Y>
      </Point>
      <Point>
        <X>261</X>
        <Y>237</Y>
      </Point>
</Sequence>
</ArrayOfSequence>

I am using accord.net mouse gesture recogination sample application, which saves the file in above xml format. I need help to convert above xml in to CSV format so i can do machine learning using accord.net Dynamic time warping. I can not figure out how to convert in to csv file. for example: 261,210,261,214,261,229,261,231

回答1:

using System.IO;
using System.Xml.Serialization;

You can do like this:

public class Sequence
{
    public Point[] SourcePath { get; set; }
}

using (FileStream fs = new FileStream(@"D:\youXMLFile.xml", FileMode.Open))
{
    XmlSerializer serializer = new XmlSerializer(typeof(Sequence[]));
    var data=(Sequence[]) serializer.Deserialize(fs);
    List<string> list = new List<string>();
    foreach(var item in data)
    {
        List<string> ss = new List<string>();
        foreach (var point in item.SourcePath) ss.Add(point.X + "," + point.Y);
        list.Add(string.Join(",", ss));
    }
    File.WriteAllLines("D:\\csvFile.csv", list);
}

回答2:

In an alternate way you can use leverage the power of XSLT to convert it,

Steps

Create an Xml stylesheet to convert xml to csv
Use XslCompiledTransform() to convert get the csv string
save the csv string to a file

You may came up with an Xslt like this, call it data.xsl

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="text" version="1.0" encoding="UTF-8"/>
  <xsl:template match="/">
    <xsl:for-each select="//Point">
      <xsl:value-of select="X"/>,<xsl:value-of select="Y"/>
      <xsl:text>&#xD;&#xA;</xsl:text>
    </xsl:for-each>
  </xsl:template>
</xsl:stylesheet>

and use the following method

public static string ToCSV(string xmlTextDate, string xsltFile)
{
  string result = string.Empty;
  var xpathDoc = new XPathDocument(xmlTextDate);
  var xsltTransform = new System.Xml.Xsl.XslCompiledTransform();
  xsltTransform.Load(xsltFile);

  using (MemoryStream ms = new MemoryStream())
  {
      var writer = new XmlTextWriter(ms, Encoding.UTF8);
      using (var rd = new StreamReader(ms))
      {
          var argList = new System.Xml.Xsl.XsltArgumentList();
          xsltTransform.Transform(xpathDoc, argList, writer);
          ms.Position = 0;
          result = rd.ReadToEnd();
      }
  }
  return result;
}

and call it like this

var csvString = ToCSV("yourfile.xml","data.xsl");

回答3:

Just create a csv file of the XML, Use System.IO and make sure the file is something like

fileName = Name + ".csv"

Have a read up and look for something like this

Path.GetTempPath(), fileName

I am a bit sketchy but that should put you on the right track

来源：https://stackoverflow.com/questions/35628637/convert-xml-file-to-csv-file-format-in-c-sharp

标签

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csv

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