问题
func(a(), b.c)
When executing the line above in the pdb debugger, using step will actually step into a, and then into the getter for b.c if its atypical (such as being a property), before actually stepping into func.
Generally I find myself using step followed by r to return from the frames I'm not interested in, and often inexplicably pass over and miss the opportunity to step directly into func.
How do I step directly into func, or what sequence of debugger commands will guarantee that I end up in func rather than passing over it?
回答1:
tb func ("temporary break at func") followed by c ("continue") should work.
回答2:
I would handle this by setting a break at the line number inside func that you're interested in, and then use continue. For example suppose your code looks like this:
110 def func(a1, a2):
111 "" docstring ""
112 first interesting line
then do this:
python -m pdb caller.py
pdb> b 112
pdb> c
来源：https://stackoverflow.com/questions/3270174/step-into-subroutine-call-but-not-calls-made-for-parameters