问题
Before you dive in, here is my question: how can I use type hints in a subclass to specify a different type on an instance attribute?
If you are unclear on what that means, read below, where I have drawn up an example to clarify things.
Full Explanation
I have an abstract class Foo
, and a subclass of Foo
called SubclassOfFoo
.
Foo
has an abstract method get_something
that returns an object of type Something
.
Something
has a subclass called SubclassOfSomething
. SubclassOfSomething
has an additional method something_special
.
SubclassOfFoo
overrides get_something
to return an object of type SubclassOfSomething
. Then, SubclassOfFoo
tries to use SubclassOfSomething
's method something_special
.
However, currently my PyCharm's inspections are reporting Unresolved attribute reference 'something_special' for class 'Something'
. I am trying to figure out the correct way to fix this.
This is all very confusing, so I have made a nice little code snippet to help here:
from abc import ABC, abstractmethod
class Something:
def __init__(self):
self.attr = 0
class SubclassOfSomething(Something):
def __init__(self):
Something.__init__(self)
def something_special(self):
self.attr = 1
class Foo(ABC):
def __init__(self):
self.my_class = self.get_something()
@abstractmethod
def get_something(self) -> Something:
pass
class SubclassOfFoo(Foo):
def __init__(self):
Foo.__init__(self)
def get_something(self) -> SubclassOfSomething:
return SubclassOfSomething()
def do_something_special(self):
self.my_class.something_special()
Basically, in order to get everything to work out, I can do one of several things:
- Remove the type hint on the return of
get_something
withinFoo
- Use a type hint in
SubclassOfFoo
forself.my_class
to clear things up - Use generics?
Option #1 is what I am trying to avoid
Option #2 is not bad, but I can't figure it out
Option #3 is also an option.
I am also open to other options, as I am sure there is a better way.
Can you please help me figure out the correct way to handle this?
What I Have Tried
To emulate option #2, I tried using typing.Type
as suggested here: Subclass in type hinting
However, this was not working for me.
回答1:
You can give a type hint on my_class
attribute in the beginning of class definition:
class SubclassOfFoo(Foo):
my_class: SubclassOfSomething # <- here
def get_something(self) -> SubclassOfSomething:
return SubclassOfSomething()
def do_something_special(self):
self.my_class.something_special()
After that there is no warning Unresolved attribute reference 'something_special' for class 'Something'
from PyCharm inspection because now my_class
is known to be SubclassOfSomething
not Something
.
回答2:
You could provide the something_special
method on Something
too, and raise a NotImplementedError
class Something:
def __init__(self):
self.attr = 0
def something_special(self):
raise NotImplementedError()
This resolves your type hinting issue, although functionally it will raise an exception at the same point (if you managed to get a Something
somehow and try to call something_special
, just will be NotImplementedError
instead of AttributeError
).
Maybe in some situations you might want to just pass
instead, depending on what something_special
actually is.
class Something:
def __init__(self):
self.attr = 0
def validate(self):
# doesn't want to perform validation
pass
class SubclassOfSomething(Something):
def __init__(self):
Something.__init__(self)
def validate(self):
if self.attr < 0:
raise ValueError()
The important underlying thing is making sure your class hierarchy conforms to a common interface - public methods on subclasses but not on parents goes against that and reduces the polymorphism of objects in your class hierarchy.
回答3:
Using generics:
from abc import ABC, abstractmethod
from typing import Generic, TypeVar
SomethingT = TypeVar('SomethingT', bound='Something')
...
class Foo(ABC, Generic[SomethingT]):
my_class: SomethingT
def __init__(self):
self.my_class = self.get_something()
@abstractmethod
def get_something(self) -> SomethingT:
pass
class SubclassOfFoo(Foo[SubclassOfSomething]):
def __init__(self):
super().__init__()
def get_something(self) -> SubclassOfSomething:
return SubclassOfSomething()
def do_something_special(self):
# inferred type of `self.my_class` will be `SubclassOfSomething`
self.my_class.something_special()
来源:https://stackoverflow.com/questions/58089300/python-how-to-override-type-hint-on-an-instance-attribute-in-a-subclass