renderpartial with null model gets passed the wrong type

问题

I have a page:

<%@ Page Inherits=\"System.Web.Mvc.View<DTOSearchResults>\" %>

And on it, the following:

<% Html.RenderPartial(\"TaskList\", Model.Tasks); %>

Here is the DTO object:

public class DTOSearchResults
{
    public string SearchTerm { get; set; }
    public IEnumerable<Task> Tasks { get; set; }

and here is the partial:

<%@ Control Language=\"C#\" Inherits=\"System.Web.Mvc.ViewUserControl<IEnumerable<Task>>\" %>

When Model.Tasks is not null, everything works fine. However when its null I get:

The model item passed into the dictionary is of type \'DTOSearchResults\' but this dictionary requires a model item of type \'System.Collections.Generic.IEnumerable`1[Task]\'.

I figured it must not know which overload to use, so I did this (see below) to be explicit, but I still get the same issue!

<% Html.RenderPartial(\"TaskList\", (object)Model.Tasks, null); %>

I know I can work around this by checking for null, or not even passing null, but that\'s not the point. Why is this happening?

回答1:

Andrew I think the problem you are getting is a result of the RenderPartial method using the calling (view)'s model to the partial view when the model you pass is null.. you can get around this odd behavior by doing:

<% Html.RenderPartial("TaskList", Model.Tasks, new ViewDataDictionary()); %>

Does that help?

回答2:

@myandmycode's answer is good, but a slightly shorter one would be

<% Html.RenderPartial("TaskList", new ViewDataDictionary(Model.Tasks)); %>

This works because the ViewDataDictionary is the thing that holds the model, and it can accept a model as a constructor parameter. This basically passes an "entire" view data dictionary, which of course only contains the possibly-null model.

回答3:

It appears that when the property of the Model you're passing in is null MVC intentionally reverts back to the "parent" Model. Apparently the MVC engine interprets a null model value as intent to use the previous one.

Slightly more details here: ASP.NET MVC, strongly typed views, partial view parameters glitch

回答4:

If you do not want to loose your previous ViewData in the partial view, you could try:

<% Html.RenderPartial("TaskList", Model.Tasks, new ViewDataDictionary(ViewData){Model = null});%>

回答5:

A solution would be to create a HtmlHelper like this:

public static MvcHtmlString Partial<T>(this HtmlHelper htmlHelper, string partialViewName, T model)
{
    ViewDataDictionary viewData = new ViewDataDictionary(htmlHelper.ViewData)
    {
        Model = model
    };
    return PartialExtensions.Partial(htmlHelper, partialViewName, model, viewData);
}

The Partial<T>(...) matched before the Partial(...) so convenient and no ambiguity error when compiling.

Personally I find it difficult to understand the behaviour - seems hard to imagine this as design choice?

回答6:

Though this has been answered, I ran across this and decided I wanted to solve this issue for my project instead of working around it with new ViewDataDictionary().

I created a set of extension methods: https://github.com/q42jaap/PartialMagic.Mvc/blob/master/PartialMagic.Mvc/PartialExtensions.cs
I also added some methods that don't call the partial if the model is null, this will save a lot of if statements.

I created them for Razor, but a couple of them should also work with aspx style views (the ones that use HelperResult probably aren't compatible).

The extension methods look like this:

@* calls the partial with Model = null *@
@Html.PartialOrNull("PartialName", null)
@* does not call the partial if the model is null *@
@Html.PartialOrDiscard("PartialName", null)

There are also methods for IEnumerable<object> models and the discard ones can also be called with a Razor lambda that allow you to wrap the partial result with some html.

Feel free to use them if you like.

回答7:

My workaround to this is:


<% Html.RenderPartial("TaskList", Model.Tasks ?? new List()); %>

来源：https://stackoverflow.com/questions/650393/renderpartial-with-null-model-gets-passed-the-wrong-type

标签

asp.net-mvc

renderpartial