问题
C# 8 introduced pattern matching, and I already found good places to use it, like this one:
private static GameType UpdateGameType(GameType gameType)
{
switch (gameType)
{
case GameType.RoyalBattleLegacy:
case GameType.RoyalBattleNew:
return GameType.RoyalBattle;
case GameType.FfaLegacy:
case GameType.FfaNew:
return GameType.Ffa;
default:
return gameType;
}
}
which then becomes
private static GameType UpdateGameType(GameType gameType) => gameType switch
{
GameType.RoyalBattleLegacy => GameType.RoyalBattle,
GameType.RoyalBattleNew => GameType.RoyalBattle,
GameType.FfaLegacy => GameType.Ffa,
GameType.FfaNew => GameType.Ffa,
_ => gameType;
};
However, you can see I now have to mention GameType.RoyalBattle
and GameType.Ffa
twice. Is there a way to handle multiple cases at once in pattern matching? I'm thinking of anything like this, but it is not valid syntax:
private static GameType UpdateGameType(GameType gameType) => gameType switch
{
GameType.RoyalBattleLegacy, GameType.RoyalBattleNew => GameType.RoyalBattle,
GameType.FfaLegacy, GameType.FfaNew => GameType.Ffa,
_ => gameType;
};
I also tried things like
[GameType.RoyalBattleLegacy, GameType.RoyalBattleNew] => GameType.RoyalBattle
or
GameType.FfaLegacy || GameType.FfaNew => GameType.Ffa
but none are valid.
Also did not find any example on this. Is it even supported?
回答1:
You can eventually use var pattern combined with case guard (when clause). Not sure if it is better than the variant with duplicate return values, but here it is:
private static GameType UpdateGameType(GameType gameType) => gameType switch
{
var v when v == GameType.RoyalBattleLegacy || v == GameType.RoyalBattleNew
=> GameType.RoyalBattle,
var v when v == GameType.FfaLegacy || v == GameType.FfaNew
=> GameType.Ffa,
_ => gameType
};
来源:https://stackoverflow.com/questions/56920902/c-sharp-8-switch-expression-handle-multiple-cases-at-once