1385. Find the Distance Value Between Two Arrays

倖福魔咒の 提交于 2020-03-27 03:26:49

Given two integer arrays arr1 and arr2, and the integer dreturn the distance value between the two arrays.

The distance value is defined as the number of elements arr1[i] such that there is not any element arr2[j] where |arr1[i]-arr2[j]| <= d.

 

Example 1:

Input: arr1 = [4,5,8], arr2 = [10,9,1,8], d = 2
Output: 2
Explanation: 
For arr1[0]=4 we have: 
|4-10|=6 > d=2 
|4-9|=5 > d=2 
|4-1|=3 > d=2 
|4-8|=4 > d=2 
For arr1[1]=5 we have: 
|5-10|=5 > d=2 
|5-9|=4 > d=2 
|5-1|=4 > d=2 
|5-8|=3 > d=2
For arr1[2]=8 we have:
|8-10|=2 <= d=2
|8-9|=1 <= d=2
|8-1|=7 > d=2
|8-8|=0 <= d=2

Example 2:

Input: arr1 = [1,4,2,3], arr2 = [-4,-3,6,10,20,30], d = 3
Output: 2

Example 3:

Input: arr1 = [2,1,100,3], arr2 = [-5,-2,10,-3,7], d = 6
Output: 1

 

Constraints:

  • 1 <= arr1.length, arr2.length <= 500
  • -10^3 <= arr1[i], arr2[j] <= 10^3
  • 0 <= d <= 100
class Solution {
    public int findTheDistanceValue(int[] arr1, int[] arr2, int d) {
        int l1 = arr1.length;
        int l2 = arr2.length;
        int res = 0;
        Arrays.sort(arr1);
        Arrays.sort(arr2);
        int tmp = 0;
        for(int i = 0; i < l1; i++){
            for(int j = l2-1; j >= 0; j--){
                if(Math.abs(arr1[i] - arr2[j]) <= d){
                   break;  
                }
                else tmp++;
            }
            if(tmp == l2) res++;
            tmp = 0;
        }
        return res;
    }
}

 

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