问题
In the following program
class ZiggyTest2 {
public static void main(String[] args){
double x = 123.456;
char c = 65;
int i = 65;
System.out.printf("%s",x);
System.out.printf("%b",x);
System.out.printf("%c",c);
System.out.printf("%5.0f",x);
System.out.printf("%d",i);
}
}
The output is
123.456trueA 12365
Can someone please explain how a double value (i.e. 123.456
) is converted to a boolean (ie. true
)
The reason I ask is because I know java does not allow numbers to be used for boolean values. For example, the following is not allowed in Java
if (5) {
//do something
}
Thanks
回答1:
for "%b" : If the argument arg is null, then the result is "false". If arg is a boolean or Boolean, then the result is the string returned by String.valueOf(). Otherwise, the result is "true".
reference
回答2:
The API documentation seems to clearly state why.
If the argument arg is null, then the result is "false". If arg is a boolean or Boolean, then the result is the string returned by String.valueOf(). Otherwise, the result is "true".
回答3:
Because the value is of type double
and this is how the %b
converter works with values of this type.
来源:https://stackoverflow.com/questions/8629995/formatting-using-printf-and-format