极简,算法模板如下:
#include<iostream>
using namespace std;
const int N = 1e6 + 10;
int n;
int q[N];
int tmp[N];
void merge_sort(int q[N], int l, int r)
{
if( l >= r ) return ;
int mid = l + r >>1;
int k = 0, i = l, j = mid +1;
merge_sort(q, l, mid), merge_sort(q, mid + 1, r);
while( i <= mid && j <= r)
if( q[i] < q[j] ) tmp[k ++ ] = q[i ++ ];
else tmp[k ++ ] = q[j ++ ];
while(i <= mid) tmp[k ++ ] = q[i ++ ];
while(j <= r) tmp[k++ ] = q[j ++ ];
for(int i = l, j = 0; i <= r ; ++i, ++j) q[i] = tmp[j];
}
int main()
{
scanf("%d",&n);
for (int i=0;i<n;++i) scanf("%d",&q[i]);
merge_sort(q, 0, n-1);
for (int i=0;i<n;++i) printf("%d",q[i]);
return 0;
}
来源:CSDN
作者:何止.
链接:https://blog.csdn.net/weixin_43900387/article/details/104703060