问题
I have such string:
{
"debug":"false",
"switchTime":"2017-04-12 17:04:42.896026"
}
I'm trying to get object in such approach:
new ObjectMapper().readValue(string, MyObject.class);
And MyObject class:
class MyObject {
private Boolean debug;
private Timestamp switchTime;
//...getters, setters, constructors
}
I have such exception:
com.fasterxml.jackson.databind.exc.InvalidFormatException:
Can not deserialize value of type java.sql.Timestamp from String
"2017-04-12 17:04:42.896026": not a valid representation (error:
Failed to parse Date value '2017-04-12 17:04:42.896026':
Can not parse date "2017-04-12 17:04:42.896026Z": while it seems
to fit format 'yyyy-MM-dd'T'HH:mm:ss.SSS'Z'',
parsing fails (leniency? null)) at [Source:
{"debug":"false", "switchTime":"2017-04-12 17:04:42.896026"};
I don't understand why...If i use in debug mode Timestamp.valueOf() with "2017-04-12 17:04:42.896026" - i have success
回答1:
I think you need to set the expected date/time format using @JsonFormat
annotation as shown below.
class MyObject {
private Boolean debug;
@JsonFormat(pattern="yyyy-MM-dd HH:mm:ss.SSS")
private Timestamp switchTime;
//...getters, setters, constructors
}
You can also set timezone as @JsonFormat(pattern="yyyy-MM-dd HH:mm:ss.SSS",timezone="PST")
回答2:
First of all get timestamp as a string then convert into desired timestamp patter.
class MyObject {
private Boolean debug;
private String switchTime;
//...getters, setters, constructors
}
convert string to desired timestamp format using follweing code
try{
SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss.SSS");
Date parsedDate = dateFormat.parse(switchTime);
Timestamp timestamp = new java.sql.Timestamp(parsedDate.getTime());
}catch(Exception e){
}
回答3:
The value that you see in debug mode is "toString()" version of actual value of timestamp, so don't rely on what you inspect in debug mode. You can use @JsonFormat annotation that helps you to convert your timestamp with specified format. You need to take care of timezones also while converting!
来源:https://stackoverflow.com/questions/43373270/jackson-deserialize-json-with-timestamp-field