问题
Breakpoint 1, 0x00007ffff7de8060 in __libc_start_main () from /usr/lib/libc.so.6
(gdb) r
The program being debugged has been started already.
Start it from the beginning? (y or n) y
Starting program: /home/firstlove/projects/org-ioslide/example/a.out
Breakpoint 1, 0x00007ffff7de8060 in __libc_start_main () from /usr/lib/libc.so.6
(gdb) r
The program being debugged has been started already.
Start it from the beginning? (y or n) y
Starting program: /home/firstlove/projects/org-ioslide/example/a.out
Breakpoint 1, 0x00007ffff7de8060 in __libc_start_main () from /usr/lib/libc.so.6
(gdb) Quit
(gdb) quit
A debugging session is active.
Inferior 1 [process 16372] will be killed.
Quit anyway? (y or n) y
firstlove-pc% cat /proc/sys/kernel/randomize_va_space
2
IIUC, ASLR should randomize all address, including the one of libc.so
, but I found that the address of __libc_start_main()
is always 0x00007ffff7de8060
on my Linux machine, why? What is wrong?
回答1:
When you run a program inside gdb
, gdb
tries to help you debugging by disabling address randomization. You can use the following command to enable it (effective from the next run of the program):
set disable-randomization off
来源:https://stackoverflow.com/questions/59772399/why-is-the-address-of-libc-start-main-always-the-same-inside-gdb-even-though-a