问题
I am trying to pass a different model to the partial view from a view. I have two separate controller actions for both of them and two different view models. But when I call the partial view from within the view it gives me the error
The model item passed into the dictionary is of type 'Application.ViewModels.Model1ViewModel', but this dictionary requires a model item of type 'Application.ViewModels.PartialViewModel'.
I am calling it like this:
@Html.Partial("_CreateUniFunctionPartial")
the model call in the view is
@model Application.ViewModels.Model1ViewModel
and model in partial view file is
@model Application.ViewModels.PartialViewModel
I am not sure how to pass the partial view so it doesnt give this error.
EDIT
Partial view
@model Application.ViewModels.PartialViewModel
@using (Html.BeginForm("partialview", "ApplicationDetail", FormMethod.Post))
{
<div class="form-horizontal">
<h4>UniFunctionViewModel</h4>
<hr />
@Html.ValidationSummary(true)
<div class="form-group">
@Html.LabelFor(model => model.detail, new { @class = "control-label col-md-2" })
<div class="col-md-10">
@Html.TextBoxFor(model => model.detail, new { @placeholder = "Further Information" })
@Html.ValidationMessageFor(model => model.detail)
</div>
</div>
</div>
}
回答1:
you are using the right method but not passing in the right arguments
you might want to try it like this:
@Html.Partial("~/[path_to_root_only_if_exists]/_CreateUniFunctionPartial.cshtml", new Application.ViewModels.PartialViewModel())
if you do not pass in a model, it will automatically take the one from its parent, which in your case is
Application.ViewModels.Model1ViewModel
回答2:
One thing you will need to do is regenerate a model or utilize a property in the model. For example:
public class OuterViewModel
{
public InnerViewModel InnerViewModel { get; set; }
}
public class InnerViewModel
{
public string SomeProperty { get; set; }
}
In the top page, you can accept the OuterViewModel, then pass the InnerViewModel to the Partial.
Outer.cshtml:
@model OuterViewModel
@Html.Partial("_InnerPartial", Model.InnerViewModel)
_InnerPartial.cshtml:
@model InnerViewModel
@using (Html.BeginForm("Inner", "Controller"))
{
<div>
@Html.AntiForgeryToken()
@Html.TextBoxFor(m => m.SomeProperty)
<input type="submit" value="Save" />
</div>
}
回答3:
This is quite simple to do. There is a html directive which can render a partial view. Following is the code sample:
@Html.Partial("nameOfPartial", Model)
Now here Model could be from your main controller.
or you can define a new controller action with partialviewresult as return type and try to render it in the page like this:
@{Html.RenderAction("Someaction", "somecontroller");}
来源:https://stackoverflow.com/questions/23594228/pass-a-different-model-to-the-partial-view