Exception slicing - is this due to generated copy constructor?

问题

I've just fixed a very subtle bug in our code, caused by slicing of an exception, and I now want to make sure I understand exactly what was happening.

Here's our base exception class, a derived class, and relevant functions:

class Exception
{
public:
  // construction
  Exception(int code, const char* format="", ...);
  virtual ~Exception(void);

  <snip - get/set routines and print function>

protected:
private:
  int mCode;                // thrower sets this
  char mMessage[Exception::MessageLen]; // thrower says this FIXME: use String
};

class Derived : public Exception {
public:
  Derived (const char* throwerSays) : Exception(1, throwerSays) {};
};

void innercall {
  <do stuff>
  throw Derived("Bad things happened!");
}

void outercall {
  try {
    innercall();
  }
  catch(Exception& e)
  {
    printf("Exception seen here! %s %d\n", __FILE__, __LINE__);
    throw e;
  }
}

The bug was of course that outercall ends up throwing an Exception, instead of a Derived. My bug resulted from higher in the call stack attempts to catch the Derived failing.

Now, I just want to make sure I understand - I believe that at the 'throw e' line, a new Exception object is being created, using a default copy constructor. Is that what's really going on?

If so, am I allowed to lock out copy constructors for objects that will be thrown? I'd really prefer this not happen again, and our code has no reason to copy Exception objects (that I know of).

Please, no comments on the fact that we have our own exception hierarchy. That's a bit of old design that I'm working to correct (I'm making good progress. I've gotten rid of the home-grown string class, and many of the home-grown containers.)

UPDATE: To be clear, I had fixed the bug (by changing 'throw e' to 'throw') before I ever asked the question. I was just looking for confirmation of what was going on.

回答1:

When you throw an object, you're actually throwing a copy of the object, not the original. Think about it - the original object is on the stack, but the stack is being unwound and invalidated.

I believe this is part of the standard, but I don't have a copy to reference.

The type of exception being thrown in the catch block is the base type of the catch, not the type of the object that was thrown. The way around this problem is to throw; rather than throw e; which will throw the original caught exception.

回答2:

A quick google suggests that yes, you're throwing the copy constructor is required and must be public. (Which makes sense, as you're initializing a copy of e and throwing that.)

Anyway, just use throw without specifying the exception object, to rethrow what was caught in the catch. Shouldn't that solve the problem?

  catch(Exception& e)
  {
    printf("Exception seen here! %s %d\n", __FILE__, __LINE__);
    throw;
  }

回答3:

Yes.

throw e;

throws an exception of the static type of e, regardless of whatever e actually is. In this case, the Derived exception is copied to an Exception using a copy constructor.

In this case you can just

throw;

to get the Derived exception bubble up correctly.

If you're interesting in polymorphical throwing in some other cases, refer to the always so useful C++ FAQ Lite.

回答4:

C++ never ceases to amaze me. I would have lost a lot of money had this been a bet on what was the behaviour!

The exception object is first copied to a temporary and you should have used throw. To quote the standard 15.1/3:

A throw-expression initializes a temporary object, called the exception object, the type of which is determined by removing any top-level cv-qualifiers from the static type of the operand of throw and adjusting the type from "array of T" or "function returning T" to "pointer to T" or "pointer to function returning T",respectively.

I think this gives rise to a very useful coding standard rule:

Base classes of an exception hierarchy should have a pure virtual destructor.

or

The copy constructor for a base class in an exception hierarchy shall be protected.

Either achieves the goal that the compiler will warn when you try to "throw e" since in the first case you cannot create an instance of an abstract class and the second because you cannot call the copy constructor.

来源：https://stackoverflow.com/questions/1095225/exception-slicing-is-this-due-to-generated-copy-constructor