Why is “3 in [3] == True” false? [duplicate]

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How do chained comparisons in Python actually work? (1 answer)

Python comparison operators chaining/grouping left to right? (1 answer)

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Shouldn't it be parsed as (3 in [3]) == True since in and == have the same precedence? It's definitely not being parsed as 3 in ([3] == True) since that raises a TypeError. How else can it be parsed?

p.s. I'm aware that PEP 8 says "Don't compare boolean values to True or False using ==." This is just an example.

This stemmed from a dicussion on this question

来源：https://stackoverflow.com/questions/60122659/why-is-3-in-3-true-false